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julsineya [31]
3 years ago
13

Assume that the total cholesterol levels for adults are normally distributed with mean cholesterol level of 51.6 ​mg/dL and stan

dard deviation 14.3 ​mg/dL. Find the probability that an individual will have a cholesterol level greater than 60 ​mg/dL.
Physics
1 answer:
Ivahew [28]3 years ago
5 0

Answer:

therefore, the probability that an individual will have a cholesterol level greater than 60 ​mg/dL.= 0.27

Explanation:

given data

Normal distribution

mean cholesterol level μ= 51.6 ​mg/dL

Standard deviation σ=  14.3 ​mg/dL

x= 60 mg/dL

We have to find out P(x>60)

We Know that P(x>a) =P(Z>(a-\mu)/\sigma)

therefore, P(x>60) =P(Z>(60-51.3)/14.3)

= P(Z>0.61)

= 1 - P(Z<0.61)

= 1 - 0.7291

= 0.27

therefore, the probability that an individual will have a cholesterol level greater than 60 ​mg/dL.= 0.27

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However, there is one type of double-replacement reaction that we can predict: the precipitation reaction. A precipitation reaction occurs when two ionic compounds are dissolved in water and form a new ionic compound that does not dissolve; this new compound falls out of solution as a solid precipitate.
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n200080 [17]

Answer:

a) \%V = 87.36\,\%, b) x = 1.248\,m, c) F_{B} = 176488.341\,N, d) Six polar bears.

Explanation:

a) The slab of ice is modelled by the Archimedes' Principles and the Newton's Laws, whose equation of equilibrium is:

\Sigma F =\rho_{w}\cdot g \cdot A \cdot x-\rho_{i}\cdot g\cdot V = 0

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\rho_{w}\cdot A \cdot x = \rho_{i}\cdot V

x = \frac{\rho_{i}\cdot V}{\rho_{w}\cdot A}

x = \frac{\left(900\,\frac{kg}{m^{3}}\right)\cdot (20\,m^{3})}{\left(1030\,\frac{kg}{m^{3}} \right)\cdot (14\,m^{2})}

x = 1.248\,m

The percentage of the volume of the ice that is submerged is:

\%V = \frac{(1.248\,m)\cdot (14\,m^{2})}{20\,m^{3}} \times 100\,\%

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b) The height of the portion of the ice that is submerged is:

x = 1.248\,m

c) The buoyant force acting on the ice is:

F_{B} = \left(1030\,\frac{kg}{m^{3}} \right)\cdot (1.248\,m)\cdot (14\,m^{2})\cdot \left(9.807\,\frac{m}{s^{2}} \right)

F_{B} = 176488.341\,N

d) The new system is modelled after the Archimedes' Principle and Newton's Laws:

\Sigma F = -n\cdot m_{bear}\cdot g-\rho_{i}\cdot V \cdot g + \rho_{w}\cdot V\cdot g = 0

The number of polar bear is cleared in the equation:

n\cdot m_{bear} = (\rho_{w} - \rho_{i})\cdot V

n = \frac{(\rho_{w}-\rho_{i})\cdot V}{m_{bear}}

n = \frac{\left(1030\,\frac{kg}{m^{3}} - 900\,\frac{kg}{m^{3}} \right)\cdot (20\,m^{3})}{400\,kg}

n = 6.5

The maximum number of polar bears that slab could support is 6.

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