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wel
3 years ago
7

If it cost $60 for 10 students to go on field trip and $70 for 20 student to go on field trip and it cost$80 for 30. How much wo

uld it cost for 40 students and 50 students to go on a field trip.
Mathematics
2 answers:
Dafna1 [17]3 years ago
8 0
I think it is $100 and $120
valina [46]3 years ago
5 0
$90 for 40. $100 for 50
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Write the six step in division
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Answer:

Divide the tens column dividend by the divisor. Multiply the divisor by the quotient in the tens place column. Subtract the product from the divisor

Step-by-step explanation:

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3 years ago
What is the slope of the line with equation y=12x
fomenos
  <span>When you have an equation of the form y = mx + b (which you do in this case), the slope is always equal to the coefficient of x, which is m or 12 in this case. Since there is no "b" in your equation, you could say that b=0, and the line is known to cross the y axis at zero. 

In case you are interested, if the equation said y = 12 x + 3 the slope of the line would still be 12 but the line would cross the y axis at 3. If the equation said y = 12x -4, the line would have a slope of 12 and would cross the y axis at -4.</span>
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3 years ago
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Harman [31]

Answer:

x = -7/2 multiplicity 2.

Step-by-step explanation:

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This is a perfect square.

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6 0
3 years ago
A company has two large computers. The slower computer can send all the company's email in 60 minutes. The faster computer can c
Lelu [443]

Answer:

If both computers are working together, it will take 24 minutes to do the job

Step-by-step explanation:

It is given that,

There are two computers.The slower computer can send all the company's email in 60 minutes.

The faster computer can complete the same job in 40 minutes

<u>To find the LCM of 40 and 60</u>

LCM (40, 60) = 120

<u>To find efficiency of 2 computers</u>

Let x be the efficiency of faster computer and y be the efficiency of faster computer

x = 120/40 = 3

y = 120/60 = 2

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Therefore efficiency of both the computer work together = x + y =5

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4 0
3 years ago
Please need help for question number 26
kherson [118]

(8,12)(14,3)


Use midpoint formula


(X1+x2/2, y1+y2/2)


Substitute with your points


(8+14/2, 12+3/2)


Solve each


(22/2,15/2)


Cancel common factor 2


(2×(4+7)/2(1),15/2)


Simplify

(4+7/1,15/2)


This is your midpoint

(11, 15/2)




3 0
3 years ago
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