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Inessa [10]
3 years ago
15

Phytoplankton are microscopic photosynthesizing organisms that typically live in the upper layers of the ocean. What trophic lev

el do phytoplankton belong to?
Primary producers
Decomposers
Primary consumers
Secondary producers
Chemistry
2 answers:
Sever21 [200]3 years ago
8 0
I think they are primary producers, as they produce biomass from inorganic compounds (CO2)
luda_lava [24]3 years ago
7 0

Answer: Primary producers

A food chain is a linear series of transfer of food and energy when one organism is consumed by the other organism in an ecosystem. The energy is distributed among different tropic levels of the food chains.

Phytoplankton is a class of unicellular simple, autotrophic organisms which are found in water of ocean, lakes and or any other freshwater body. These includes dinoflagellates, diatoms, cynobacteria, green algae and others. These organisms are abundantly present in the ecosystem in the lower most trophic level. They are called as primary producers because they are consumed by other organisms such as zooplanktons, fishes and large sea mammals.  

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Answer: I believe it’s the second one

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Explanation:

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3 years ago
Using the graphic provided,idenify the reactants of photosynthesis?
Y_Kistochka [10]

Answer:

water, carbon dioxide reacted in the presence of sun light and chlorophyll and form glucose and oxygen.

Explanation:

Photosynthesis:

It is the process in which in the presence of sun light and chlorophyll by using carbon dioxide and water plants produce the oxygen and glucose.

Carbon dioxide + water + energy →   glucose + oxygen

water is supplied through the roots, carbon dioxide collected through stomata and sun light is capture  by chloroplast.

Chemical equation:

6H₂O + 6CO₂ + energy  →   C₆H₁₂O₆ + 6O₂

it is known from balanced chemical equation that 6 moles of carbon dioxide react with the six moles of water so, the mass of water will be,

The glucose is converted into pyruvate and prod

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4 years ago
When warm air rises and cool air sinks towards earth surface. what is this known as?
iVinArrow [24]

When warm air rises and cool air sinks towards earth surface. what is this known as <u>convection currents.</u>

Explanation:

Convection currents not only occurs in the air but also in other fluids like water. In the air, they are responsible for the blowing of winds of the atmosphere . In the oceans, they are responsible for ocean currents. Convection currents also occur in the mantle and are responsible for tectonic plate movements.

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4 0
4 years ago
Calculate the weight percent of ascorbic acid in a tablet of Vitamin C from the following data:A 80 mg sample of a crushed Vitam
Lina20 [59]

Answer:

The Answer is 88%

Explanation:

The balanced ionic equation of the reaction

   IO^{3- }+ 8 I^- + 6 H^+ => 3 I^{3- }+ 3 H_2O

  I^{3-} + 2 S_2O_3^{2-} => 3 I^- + S_4O_6^{2-}

 

  C_6H_8O_6 + I^{3- }+ H_2O => C_6H_6O_6 + 3 I^- + 2 H^+

Looking at the above reactions

   The original number of moles of I^{3-} = 3 × number of moles of IO^{3-}

                                                                = 3 × volume × concentration of KIO_3

Note: The formula for number of moles is volume × concentration

                                                                =3 * \frac{40}{1000} *  0.00653 =0.000784 mol

The number of moles of I^{3-} left after its reaction with ascorbic  acid

                         = \frac{1}{2} x moles of S_2O_3^{2-}

                          = \frac{1}{2} x volume x concentration of    S_2O_3^{2-}

                          = \frac{1}{2}  * \frac{15}{1000} * 0.0510 =0.000383 \ mol

Note: The division by 1000 is to convert mill liter to liter

                             Moles of ascorbic acid = moles of I^{3-} reacted

                           = initial \ moles \ of \  I^{3-} \ - remaining \ moles \ of \ I^{3-}

                           =0.000784 - 0.000383

                          =0.000401 \ mols

              Mass =  moles \ * molar \ mass

Hence

              Mass of ascorbic acid = moles of ascorbic acid × molar mass of ascorbic acid

                                                      = 0.000401* 176.12 = 0.07055\ g

                                                      = 70.55\  mg

 Weight% of ascorbic acid = mass of ascorbic acid/mass of sample x 100%

                                             = 70.55/80  × 100%

                                              = 88.1%

                       

3 0
4 years ago
Anything helps thank you
olya-2409 [2.1K]
What do you need help on we need to know the question of your answer...
6 0
3 years ago
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