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kow [346]
3 years ago
8

A solution of acetic acid and water contains 205.0 g L-1 of acetic acid and 820.0 g L-1 of water. Compute the density of the sol

ution ( report your answer in g per mL)
Chemistry
1 answer:
LekaFEV [45]3 years ago
6 0

Answer:

\rho_t=1025000 gmL^{-1}

Explanation:

From the question we are told that:

Density of acetic acid \rho_a=205 gL^{-1}

Density of Water \rho_w=820 gL^{-1}

Generally the equation for Solution Density is mathematically given by

\rho_t= \rho_w+\rho_a

\rho_t=205+820

\rho_t=1025 gL^{-1}

\rho_t=1025000 gmL^{-1}

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What is the precipitation reaction of sodium nitrate and lead (II)?
Vadim26 [7]
The precipitation reaction of sodium nitrate and lead (II) chloride would not happen. No reaction will happen between these substances. Hope this answers the question. Have a nice day.
8 0
3 years ago
Determine the AMOUNT OF NO2, LIMITING REACTANT, AND THE AMOUNT AND NAME OF EXCESS REACTANT.
zepelin [54]

Answer:

balanced equation mole ratio 5 2 mol NO/1 mol O2

10.00 g O2 3 1 mol O2/32.00 g O2 5 0.3125 mol O2

20.00 g NO 3 1 mol NO/30.01 g NO 5 0.6664 mol NO

actual mole ratio 5 0.6664 mol NO/0.3125 mol O2 5 2.132 mol NO/1.000 mol O2

Because the actual mole ratio of NO:O2 is larger than the balanced equation mole

ratio of NO:O2, there is an excess of NO; O2 is the limiting reactant.

Mass of NO used 5 0.3125 mol O2 3 2 mol NO/1 mol O2 5 0.6250 mol NO

0.6250 mol NO 3 30.01 g NO/1 mol NO 5 18.76 g NO

Mass of NO2 produced 5 0.6250 mol NO2 3 46.01 g NO2/1 mol NO2 5 28.76 g NO2

Excess NO 5 20.00 g NO 2 18.76 g NO 5 1.24 g N

Explanation:

3 0
2 years ago
A gas occupying a volume of 656.0 mL at a pressure of 0.884 atm is allowed to expand at constant temperature until its pressure
7nadin3 [17]

Answer:

1.14 × 10³ mL

Explanation:

Step 1: Given data

  • Initial volume of the gas (V₁): 656.0 mL
  • Initial pressure of the gas (P₁): 0.884 atm
  • Final volume of the gas (V₂): ?
  • Final pressure of the gas (P₂): 0.510 atm

Step 2: Calculate the final volume of the gas

If we assume ideal behavior, we can calculate the final volume of the gas using Boyle's law.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁/P₂

V₂ = 0.884 atm × 656.0 mL/0.510 atm = 1.14 × 10³ mL

5 0
3 years ago
Can somebody plz answer this question only in 1-2 sentences! That would be great thanks so much :)
lbvjy [14]

Pure substances are substances which are homogenous in nature. They either consists of atoms of 1 kind or molecules of 1 kind. Atoms are seen in elements, where as molecules are seen in compounds like Acids, Bases, etc.

They mostly have fixed properties like boiling and melting points and are uniform in nature. :D

4 0
3 years ago
12. What is the mass number of an atom that has 4 protons, 4 electrons, and 5 neutrons?
NeTakaya

Answer:

9

Explanation:

mass number = protons + neutrons

= 4 + 5 = 9

7 0
3 years ago
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