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kow [346]
2 years ago
8

A solution of acetic acid and water contains 205.0 g L-1 of acetic acid and 820.0 g L-1 of water. Compute the density of the sol

ution ( report your answer in g per mL)
Chemistry
1 answer:
LekaFEV [45]2 years ago
6 0

Answer:

\rho_t=1025000 gmL^{-1}

Explanation:

From the question we are told that:

Density of acetic acid \rho_a=205 gL^{-1}

Density of Water \rho_w=820 gL^{-1}

Generally the equation for Solution Density is mathematically given by

\rho_t= \rho_w+\rho_a

\rho_t=205+820

\rho_t=1025 gL^{-1}

\rho_t=1025000 gmL^{-1}

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How many atoms are in 15.0 moles of C2H6O
Burka [1]
1 mole = 6.22 x 10^23 molecules (Avogadro's number)
15 moles x (6.22 x 10^23) = 9.33 x 10^24 atoms
3 0
3 years ago
Read 2 more answers
A gas occupies 40.0 mL at 150 K. What volume does it occupy at 300 K,
nlexa [21]

Answer:

.08 L or 80 ml

Explanation:

Use the equation V/t = V/t.

.04L / 150K = V / 300K

.04 / 150 * 300 = V

.08 L or 80 ml

6 0
3 years ago
. a large piece of jewelry has a mass of 132.6 g. a graduated cylinder initially contains 48.6 ml water. when the jewelry is sub
elena-s [515]

The large piece of jewelry  that has a mass of 132.6 g and when is submerged in a graduated cylinder that initially contains 48.6 ml water and the volume increases to 61.2 ml once the piece of jewelry is submerged, has a density of: 10.523 g/ml

To solve this problem the formulas and the procedures that we have to use  are:

  • v = v(f)-v(i)
  • d = m/v

Where:

  • d= density
  • m= mass
  • v= volume
  • v(f) = final volume
  • v(i) = initial volume

Information about the problem:

  • m = 132.6 g
  • v(i) = 48.6 ml
  • v(f) = 61.2 ml
  • v = ?
  • d =?

Applying the volume formula we get:

v = v(f)-v(i)

v = 61.2 ml - 48.6 ml

v = 12.6 ml

Applying the density  formula we get:

d = m/v

d = 132.6 g/12.6 ml

d = 10.523 g/ml

<h3>What is density?</h3>

It is a physical quantity that expresses the ratio of the body mass to the volume it occupies.

Learn more about density in: brainly.com/question/1354972

#SPJ4

3 0
1 year ago
Approximately how many particles are in 2 moles?
schepotkina [342]

Answer:

1.2\times10^2^4 particles in 2 moles.

Explanation:

The number of particles that are contained in one mole, the international unit of amount of substance: by definition, exactly 6.022×10²³, and it is dimensionless. It is named after the scientist Amedeo Avogadro.

It is also known as Avogadro's constant.

∴ Number of particles in one mole = 6.022\times10^2^3

∴ Number of particles in 2 mole = 2 times Number of particles in one mole

∴ Number of particles in 2 mole=2\times6.022\times10^2^3=12.044\times10^2^3\approx1.2\times10^2^4

Hence there are 1.2\times10^2^4 particles in 2 moles.

4 0
3 years ago
Read 2 more answers
Please help<br> It’s super quick
UkoKoshka [18]

Answer:

1. a

Explanation:

2. c

7 0
3 years ago
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