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Naily [24]
2 years ago
13

Which law states that the volume and absolute temperature of a fixed quantity of gas are directly proportional under constant pr

essure conditions?
Boyle’s law
Charles’s law
Dalton’s law
Gay-Lussac’s law
Chemistry
2 answers:
lions [1.4K]2 years ago
8 0

Charles's Law i think

MAXImum [283]2 years ago
5 0

Answer is: Charles’s law.

Charle's law (the temperature-volume law): the volume of a given amount of gas held at constant pressure is directly proportional to the Kelvin temperature:  V₁/T₁ = V₂/T₂.  

For example:

V₁(gas) = 20.0 L; initial volume.

T₁(gas) = 280 K.; initial temperature

V₂(gas) = 10.0 L; final volume

T₂(gas) = ?; final temperature.

20.0 L/ 280 K = 10.0 L / T₂.  

T₂ = 140 K.  

As the volume goes down, the temperature also goes down, and vice-versa.  

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2. In the reaction NO + NO2 ⇌ N2O3, an experiment finds equilibrium concentrations of [NO] = 3.8 M, [NO2] = 3.9 M, and [N2O3] =
notsponge [240]
Kc= concentration  of  product  divided  by  concentration   of  reactant
NO +  NO2  ---->  N2O3

Kc =(N2O3)  /  (No)(NO2)

Kc= ( 1.3  )/{ (3.9)(3.8) }

Kc=0.088 (  answer  B)
4 0
3 years ago
Read 2 more answers
What is percentage composition?
blondinia [14]

Answer:

The percent composition of a component in a compound is the percent of the total mass of the compound that is due to that component. To calculate the percent composition of a component in a compound: Find the molar mass of the compound by adding up the masses of each atom.

7 0
3 years ago
A hydrocarbon contains 85.7% carbon and the remainder
Viefleur [7K]

Answer:

CH₂ ;  67.1 %

Explanation:

To determine the empirical formula we need to find what the mole ratio is in whole numbers of the atoms in the compound. To do that we will first need the atomic weights of C and H and then perform our calculation

Assume 100 grams of the compound.

# mol C = 85.7 g / 12.01 g/mol = 7.14 mol

# mol H = 14.3 g /  1.008 g/mol = 14.19 mol

The proportion is 14.9 mol H/ 7.14 mol C = 2 mol H/ 1 mol C

So the empirical formula is CH₂

For the second part we will need to first calculate the theoretical yield for the 12.03 g NaBH₄  reacted and then calculate the percent yield given the 0.295 g B₂H₆ produced.

We need to calculate the moles of  NaBH₄ ( M.W = 37.83 g/mol )

1.203 g  NaBH₄ / 37.83 g/mol =  0.0318 mol

Theoretical yield from balanced chemical equation:

0.0318 mol NaBH₄ x 1 mol B₂H₆ / mol NaBH₄ = 0.0159 mol B₂H₆

Theoretical mass yield B₂H₆ = 0.0159 mol x 27.66 g/ mol =  0.440 g

% yield = 0.295 g/ 0.440 g x 100 = 67.1 %

6 0
3 years ago
A steel cylinder of oxygen is being store in a room at 25.0 °C under a pressure of 1250 atm. What pressure would be exerted by t
Rudik [331]

Answer:

P₂ = 1312.88 atm

Explanation:

Given data:

Initial temperature = 25°C

Initial pressure = 1250 atm

Final temperature = 40°C

Final pressure = ?

Solution:

Initial temperature = 25°C (25+273.15 = 298.15 K)

Final temperature = 40°C ( 40+273.15 = 313.15 k)

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

1250 atm / 298.15 K = P₂/313.15 K

P₂ = 1250 atm × 313.15 K / 298.15 K

P₂ = 391437.5 atm. K /298.15 K

P₂ = 1312.88 atm

6 0
3 years ago
Question 1 (1 point)
Marizza181 [45]
Both ehhevshahahbsbdvhshs
4 0
2 years ago
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