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Naily [24]
3 years ago
13

Which law states that the volume and absolute temperature of a fixed quantity of gas are directly proportional under constant pr

essure conditions?
Boyle’s law
Charles’s law
Dalton’s law
Gay-Lussac’s law
Chemistry
2 answers:
lions [1.4K]3 years ago
8 0

Charles's Law i think

MAXImum [283]3 years ago
5 0

Answer is: Charles’s law.

Charle's law (the temperature-volume law): the volume of a given amount of gas held at constant pressure is directly proportional to the Kelvin temperature:  V₁/T₁ = V₂/T₂.  

For example:

V₁(gas) = 20.0 L; initial volume.

T₁(gas) = 280 K.; initial temperature

V₂(gas) = 10.0 L; final volume

T₂(gas) = ?; final temperature.

20.0 L/ 280 K = 10.0 L / T₂.  

T₂ = 140 K.  

As the volume goes down, the temperature also goes down, and vice-versa.  

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How many grams of HNO3 are produced when 59.0 g of NO2 completely reacts?
Anettt [7]

Answer:

53.7 grams of HNO3 will be produced

Explanation:

Step 1: Data given

Mass of NO2 = 59.0 grams

Molar mass NO2 = 46.0 g/mol

Step 2: The balanced equation

3NO2 + H2O→ 2HNO3 + NO

Step 3: Calculate moles NO2

Moles NO2 = 59.0 grams / 46.0 g/mol

Moles NO2 = 1.28 moles

Step 4: Calculate moles HNO3

For 3 moles NO2 we need 1 mol H2O to produce 2 moles HNO3 and 1 mol NO

For 1.28 moles NO2 we'll have 2/3 * 1.28 =0.853 moles HNO3

Step 7: Calculate mass HNO3

Mass HNO3 = 0.853 moles * 63.01 g/mol

Mass HNO3 = 53.7 grams

53.7 grams of HNO3 will be produced

3 0
3 years ago
8. What is the volume of 5.6 moles of carbon dioxide gas at STP?
pshichka [43]

Answer:

125.5 ×10^-3 m^3= 0.1255 m^3

Explanation:

Volume=5.6mol×22.414dm^3

=125.5dm^3

7 0
3 years ago
If the temperature on 244 mL of a gas is changed to 488 mL and 6 atm, at constant
Fittoniya [83]

Answer:

<h2>12 atm</h2>

Explanation:

To find the initial pressure we use the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the initial pressure

P_1 =  \frac{P_2V_2}{V_1}  \\

From the question we have

P_1 =  \frac{488 \times 6}{244}  =  \frac{2928}{244}  \\

We have the final answer as

<h3>12 atm</h3>

Hope this helps you

6 0
3 years ago
Determine the empirical formula of a compound containing 24.74% potassium, 34.74% manganese, and 40.50% oxygen. What is the name
AlexFokin [52]
The answer would be KMnO4, please let me know if you would like me to explain how i got this
4 0
3 years ago
If you mix a 25.0mL sample of a 1.20m potassium sulfide solution with 15.0 mL of a 0.900m basium nitrate solution and the reacti
ddd [48]

Answer:

Limiting reagent: barium nitrate

Theoretical yield: 2.29 g BaS

Percent yield: 87%

Explanation:

The corrected balanced reaction equation is:

K₂S + Ba(NO₃)₂ ⇒ 2KNO₃ + BaS

The amount of potassium sulfide added is:

(25.0 mL)(1.20mol/L) = 30 mmol

The amount of barium nitrate added is:

(15.0mL)(0.900mol/L = 13.5 mmol

Since the reactant react in a 1:1 molar ratio, barium nitrate is the limiting reagent. If all of the limiting reagent reacts, the amount of barium sulfide produced is:

(13.5 mmol Ba(NO₃)₂)(BaS/Ba(NO₃)₂ ) = 13.5 mmol BaS

Converting this amount to grams gives the theoretical yield of BaS (molar mass 169.39 g/mol).

(13.5 mmol)(169.39 g/mol)(1g/1000mg) = 2.29 g BaS

The percent yield is calculated as follows:

(actual yield) / (theoretical yield) x 100%

(2.0 g) / (2.29 g) x 100% = 87%

6 0
3 years ago
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