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3 years ago

How many 2º alkyl bromides, neglecting stereoisomers, exist with the formula c6h13br?

Chemistry

1 answer:

deff fn [24]3 years ago

5 0

Secondary alkyl halide will be which have carbon attached to two other carbon atoms and the bromine is attached to such carbon.

So in case of bromo-hexane the following will be 2 degree or secondary alkyl halide

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One hundred students were surveyed about who they would vote for. What is

GuDViN [60]

Hey hope this helps ⬇️

6 0

4 years ago

List the steps you would use to design a controlled experiment that would address the question, “will fertilizer added to the so

SVETLANKA909090 [29]

First I would have a pot of soil and a carrot (without fertilizer) then a pot of soli ,with fertilizer and a carrot. Then I would watch them for the same amount of time and identify weather the soil impacted the decomposition of the carrot and repeat this twice.
Same size pots
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5 0

3 years ago

A sample of helium has a volume of 5 liters and a pressure of 699 mmHg. If the final volume is 5.7 Liters, its final temperature

malfutka [58]

Answer:

The initial temperature of helium was T1 = 232.23 K

Explanation:

Given data:

Initial volume V1 = 5 L

Initial pressure P1 = 699 mmHg

Final pressure P2 = 800 mmHg

Final volume V2 = 5.7 L

Final temperature T2= 303 K

Initial temperature T1 = ?

Solution:

Formula:

P1V1/T1 = P2V2/T2

T1 = T2 × P1V1/P2V2

T1 = 303 K × 699 mmHg × 5 L / 800 mmHg × 5.7 L

T1 = 1058985/ 4560

T1 = 232.23 K

initial temperature of helium was 232.23 k.

6 0

3 years ago

Using 3 O2 molecules and 5 H2 molecules, how many water molecules can be produced? Do you have any left over?

makvit [3.9K]

Answer:

5 molecules of H₂O can be produced

0.5 molecules of O₂ did not reacted

Explanation:

The reaction is: 2H₂(g) + O₂(g) → 2H₂O (g)

Firstly we determine the limiting reactant:

2 moles of hydrogen need 1 mol of oxygen to react

We must know the moles of each.

6.02ₓ10²³ molecules is 1 mol

3 molecules are ____ 3 /6.02ₓ10²³ = 4.98×10⁻²⁴ moles O₂

5 molecules are ____ 5 / 6.02ₓ10²³ = 8.30×10⁻²⁴ moles H₂

2 moles of H₂ need 1 mol of O₂

Then 8.30×10⁻²⁴ moles of H₂ must need (8.30×10⁻²⁴ .1) / 2 = 4.15×10⁻²⁴ moles O₂. It is ok, because I have 4.98×10⁻²⁴ moles O₂. Oxygen is the reagent in excess, so the limiting is the H₂

1 moles of O₂ needs 2 moles of H₂ to react

Then, 4.98×10⁻²⁴ moles of O₂ must need (4.98×10⁻²⁴ .2) / 1 =9.96×10⁻²⁴ moles of H₂, we don't have enough H₂

So, in the reaction ratio is 2:2.

8.30×10⁻²⁴ moles of H₂ will produce 8.30×10⁻²⁴ moles H₂O

1 mol has 6.02×10²³ molecules

8.30×10⁻²⁴ must have (8.30×10⁻²⁴ . NA) = 5 molecules

The reagent in excess is the O₂. These means that there is oxygen that has not reacted.

We have 4.98×10⁻²⁴ moles O₂ and we used 4.15×10⁻²⁴ moles.

(4.98×10⁻²⁴ - 4.15×10⁻²⁴) = 0.83×10⁻²⁴ moles of oxgen hasn't reacted.

1 mol is contained by NA molecules

0.83×10⁻²⁴ moles are contained by (0.83×10⁻²⁴ . 6.02×10²³) = 0.5 molecules

6 0

3 years ago

Read 2 more answers

Question 6

kompoz [17]

Considering the combined law equation, the new temperature is -244.56 °C or 28.44 K.

<h3>Boyle's law</h3>

Boyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant: if the pressure increases, the volume decreases while if the pressure decreases, the volume increases.

Mathematically, this law states that the multiplication of pressure by volume is constant:

P×V=k

<h3>Charles's law</h3>

Charles's law states that the volume is directly proportional to the temperature of the gas: if the temperature increases, the volume of the gas increases while if the temperature of the gas decreases, the volume decreases.

Mathematically, Charles' law states that the ratio of volume to temperature is constant:

$\frac{V}{T} =k$

<h3>Gay-Lussac's law </h3>

Gay-Lussac's law states that the pressure of a gas is directly proportional to its temperature: increasing the temperature will increase the pressure, while decreasing the temperature will decrease the pressure.

Mathematically, Gay-Lussac's law states that the ratio of pressure to temperature is constant:

$\frac{P}{T} =k$