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-Dominant- [34]
3 years ago
10

A deck of cards has 52 cards. There are 4 suits, diamonds, hearts, clubs and spades. Each suit has 13 cards. What is the probabi

lity that I will randomly pick a 2, put it back, then randomly pick a 4?
Mathematics
1 answer:
Papessa [141]3 years ago
4 0

Answer: 2%, ROUNDED

Step-by-step explanation:

You must divide 100 (whole percent) by 52 (Cards in a Deck) and you will get 1.92307692308%. But if we round it, we get 2%.

So the answer is 2%.

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Helppppppppppppppppp
iris [78.8K]
<h3>Answer:</h3>

A. None of the factors were negative

because when you multiply or divide an inequality by a negative number you must flip the inequality sign.

Hope this helps you! :)

4 0
3 years ago
Either enter an exact answer in terms of pi or use 3.14 for pi and round your final answer to the nearest hundredth.
SVETLANKA909090 [29]

Answer:

18.85 units 3

Step-by-step explanation:

7 0
3 years ago
You can ride your bike around your block twice and the whole neighborhood once in 10 minutes. You can ride your bike around your
Bond [772]
I THINK,4=31
1=?
(1*31)/4=x
X=31/4
X=7.75minute to ride around the neighborhood once
It may not be correct
6 0
2 years ago
Find the constant of proportionality for the table and write in the form y = kx.
atroni [7]

Answer:

y=4x

Step-by-step explanation:

it's enough to use first column (x=6, y=24). Inserting this data into equation y=kx, we can calculate k.

24=k*6

6k = 24

k = 24/6

k = 4

6 0
3 years ago
How many enantiomeric pairs are possible for an aldohexose?<br> a.2<br> b.4<br> c.8<br> d.16?
seraphim [82]
Based on this question, one thing that we would seriously consider would be the fact of first, doing 2^4 first. By doing this, it would then give us our answer as 16. By us understanding this point of view, we would then consider that this would then be your answer. That would then include that there would then be 16 pairs of the "enantiomeric pairs", and that would then be the possible estimate.

<span>a.2
b.4
c.8
d.16</span>
4 0
3 years ago
Read 2 more answers
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