→ 
Explanation:
- The products formed are chromic chloride and cobalt.
Chromium + Cobaltous Chloride = Chromic Chloride + Cobalt
- Type of reaction is Single Displacement (Substitution) which is there is a displacement of one atom.
Reactants used in the reaction are -
- Chromium
- Cobaltous Chloride
Products formed in the reaction are -
- Chromic Chloride
- Cobalt
Hence, the chemical reaction is as follows -
→
For balancing the above chemical equation we need to add a coefficient of 2 in front of chromium and of 3 in front of cobalt(II)chloride on right-hand-side while of 2 in front of chromium chloride and of 3 in front of carbon monoxide on left-hand-side of the equation.
Hence, the balanced equation is -
→
That is a steep slope for sure, no doubt about it. Hope this helps!
Answer:
the equilibrium constant is 1.8 x 10⁻5 and strongly favor the reactants.
Explanation:
the chemical reaction provided for the two equation are the same but different direction i.e a reversible reaction. Assuming, the mass of reactants and product and temperature remain constant.
therefore, the equilibrium constant K, is 1.8 x 10⁻5. this is a very small value of K, thereby strongly favor the backward direction to form reactant.
Transcribed image text: Four liquids are described in the table below. Use the second column of the table to explain the order of their freezing points, and the third column to explain the order of their boiling points. For example, select '1' in the second column next to the liquid with the lowest freezing point. Select '2' in the second column next to the liquid with the next higher freezing point, and so on. In the third column, select '1' next to the liquid with the lowest boiling point, '2' next to the liquid with the next higher boiling point, and so on. Note: the density of water is 1.00g/mL .
To find the molecular formula from the empirical formula, you need to find a multiple (x) that will give you the molar mass of the compound which in the question is 54 g/mol.
If C₂H₃ is the empirical formula
molar mass of empirical formula = (12 × 2) + (1 × 3) g/mol
= 27 g/mol
let x = multiple
let molecular formula = C₂ₓ H₃ₓ
multiple = molecular mass ÷ empirical mass
= 54 g/mol ÷ 27 g/mol
= 2
If molecular formula = C₂ₓ H₃ₓ
then molecular formula = C₂₍₂₎H₃₍₂₎
= <span>C₄H</span>₆
