<h3>
Answer:</h3>
78.75 K
<h3>
Explanation:</h3>
<u>We are given;</u>
- Initial pressure, P₁ = 500 torr
- Initial temperature,T₁ = 225 K
- Initial volume, V₁ = 3.3 L
- Final volume, V₂ = 2.75 L
- Final pressure, P₂ = 210 torr
We are required to calculate the new temperature, T₂
- To find the new temperature, T₂ we are going to use the combined gas law;
- According to the combined gas law;
P₁V₁/T₁ = P₂V₂/T₂
We can calculate the new temperature, T₂;
Rearranging the formula;
T₂ =(P₂V₂T₁) ÷ (P₁V₁)
= (210 torr × 2.75 L × 225 K) ÷ (500 torr × 3.3 L)
= 78.75 K
Therefore, the new volume of the sample is 78.75 K
2 moles x 6.02 x 10^23 maybe
Sodium has 11 protons and Chlorine has 17.
Answer:
240 N/m
Explanation:
Using the formula as follows:
U = ½kx²
Where;
U = elastic potential energy (J)
K = spring constant (N/m)
x = stretched displacement (m)
According to the information provided in this question,
U = 35J
x = 0.54m
k = ?
U = ½kx²
35 = ½ × k × 0.54²
35 = ½ × k × 0.2916
35 = 0.2916k/2
70 = 0.2916k
k = 70 ÷ 0.2916
k = 240.05
To 2s.f, the spring constant (k) = 240 N/m.
