What is the percent composition by mass of sulfur in the compound mgso4
1 answer:
Answer:
26.7% is the percent composition by mass of sulfur in a compound named magnesium sulfate.
Explanation:
Molar mass of compound = 120 g/mol
Number of sulfur atom = 1
Atomic mass of sulfur = 32 g/mol
Percentage of element in compound :
Sulfur :
26.7% is the percent composition by mass of sulfur in a compound named magnesium sulfate.
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Number of neutrons=41, and it is metalloid
<h3>Further explanation</h3>Group 14⇒valence electron = 4(ns²np²)
Period 4⇒n=4
So electron configuration of the element :
1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p² = 32 electron=atomic number
The element with atomic number 32, which is in period 4 and group 14 is Ge-Germanium
There are seven elements that can be classified as metalloids, namely boron (B), silicon (Si), germanium (Ge), arsenic (As), antimony (Sb), tellurium (Te), and polonium (Po).
While the mass number: 73
So the number of neutrons = mass number-atomic number
Answer:
D
Explanation:
We must study the reaction pictured in the question closely before we begin to attempt to answer the question.
Now, the reaction is a free radical reaction. This implies that only one electron is transferred. The transfer of one electron is shown using a half arrow rather than a full arrow. The both species are radicals (odd electron species) and contribute one electron each.
Hence we must show electron movements in both species using a half arrow.
