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marissa [1.9K]
3 years ago
11

How many numbers does positive atoms have

Chemistry
1 answer:
anastassius [24]3 years ago
7 0
I'm not sure I'm sorry for that but I found this http://www.chem4kids.com/files/atom_ions.html
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A child pushes a desk with a force of 15 N to the right. The desk accelerates to the right. Which of the following statements co
ratelena [41]

Answer:

The answer to your question is: number 1

Explanation:

Third law of Newton: says that for every action ,there is an equal and opposite reaction.

So, if the child is pushing an object to the right, it will recipe the same amount of force that he is exerting to the object but in opposite direction.

Number 2 and 3 are incorrect because, because the third law of Newton says "an equal and opposite reaction", not slightly more or less.

Number 4 is wrong, it is not in agreement with Newton's third law of motion.

5 0
3 years ago
Which of the following is true about two neutral atoms of the element gold? (1 point) The nucleus is missing in both. Each has a
klio [65]

i have the same question idk the anwser tho

5 0
3 years ago
I have my chemistry EOC tomorrow, and I need to know how to calculate the molar mass of a compound. Specifically ones set up lik
yuradex [85]

Answer:

357.475

Explanation:

First you need periodic table and you have to look for mass

Fe = 3 x 55.845 = 167.535

P = 2  x 30.97 = 61.94

o = 4 x 2 so 8 oxygen =  8 x 16 = 128

add all and you get 357.475

6 0
3 years ago
Ideal gas (n 2.388 moles) is heated at constant volume from T1 299.5 K to final temperature T2 369.5 K. Calculate the work and h
bija089 [108]

Answer : The work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.

Explanation :

(a) At constant volume condition the entropy change of the gas is:

\Delta S=-n\times C_v\ln \frac{T_2}{T_1}

We know that,

The relation between the C_p\text{ and }C_v for an ideal gas are :

C_p-C_v=R

As we are given :

C_p=28.253J/K.mole

28.253J/K.mole-C_v=8.314J/K.mole

C_v=19.939J/K.mole

Now we have to calculate the entropy change of the gas.

\Delta S=-n\times C_v\ln \frac{T_2}{T_1}

\Delta S=-2.388\times 19.939J/K.mole\ln \frac{369.5K}{299.5K}=-10J

(b) As we know that, the work done for isochoric (constant volume) is equal to zero. (w=-pdV)

(C) Heat during the process will be,

q=n\times C_v\times (T_2-T_1)=2.388mole\times 19.939J/K.mole\times (369.5-299.5)K= 3333.003J

Therefore, the work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.

7 0
3 years ago
Safety is a concern around electronic equipment of all types. What particular safety hazard may exist A. Laser light B. High vol
omeli [17]
All of the above. If you are going to narrow it down, it would be high voltage and radioactivity.
7 0
3 years ago
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