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alexira [117]
3 years ago
10

How can you tell if a number is divisible by 3

Mathematics
2 answers:
Pepsi [2]3 years ago
6 0
Add up the numbers and if the sum is divisible by 3 the original number is also divisible by 3.

ex: 357÷3

3+5+7=15
15÷3=5

so 357 is divisible by 3.
Molodets [167]3 years ago
6 0
If the sum of the numbers can be divisible by 3, Then the number itself must also be divisible by 3.
EX. Is 1,530 divisible by 3?
*Well lets see, 1+5+3+0=9 <span> Since 9 is divisible by 3, we know that 1,530 is divisible by 3.*
 </span>
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Jimmy eats seven cookies every three minutes. How long does it take him to eat 28 cookies?
scoray [572]
28 / 7 = 4

3 x 4 = 12


It’ll take him 12 minutes
8 0
3 years ago
Read 2 more answers
Simplify negative 3 over 5 ÷ 7 over 6.
Karo-lina-s [1.5K]
(-3/5)/7/6

= -3/5 x 6/7
= -18/35
8 0
3 years ago
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The city has an average of 13 days of rainfall for April.
zhenek [66]

Using the Poisson distribution, we have that:

  • There is a 0.0859 = 8.59% probability of having exactly 10 days of precipitation in the month of April.
  • There is a 0.00022 = 0.022% probability of having less than three days of precipitation in the month of April.
  • There is a 0.2364 = 23.64% probability of having more than 15 days of precipitation in the month of April.

<h3>What is the Poisson distribution?</h3>

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

The parameters are:

  • x is the number of successes
  • e = 2.71828 is the Euler number
  • \mu is the mean in the given interval.

For this problem, the mean is given as follows:

\mu = 13

The probability of having exactly 10 days of precipitation in the month of April is P(X = 10), hence:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

P(X = 10) = \frac{e^{-13}13^{10}}{(10)!} = 0.0859

There is a 0.0859 = 8.59% probability of having exactly 10 days of precipitation in the month of April.

The probability of having less than three days of precipitation in the month of April is:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-13}13^{0}}{(0)!} \ approx 0

P(X = 1) = \frac{e^{-13}13^{1}}{(1)!} = 0.00003

P(X = 2) = \frac{e^{-13}13^{2}}{(2)!} = 0.00019

Then:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0 + 0.00003 + 0.00019 = 0.00022

There is a 0.00022 = 0.022% probability of having less than three days of precipitation in the month of April.

For more than 15 days, the probability is:

P(X > 15) = P(X = 16) + P(X = 17) + ... + P(X = 20)

Applying the formula for each of these values and adding them, we have that P(X > 15) = 0.2364, hence:

There is a 0.2364 = 23.64% probability of having more than 15 days of precipitation in the month of April.

More can be learned about the Poisson distribution at brainly.com/question/13971530

#SPJ1

6 0
2 years ago
When you earn money you pay income tax.
Nesterboy [21]
20% of £37500 = 20/100 x 37500 = £7500 (TAX)
40% of £112500 = 40/100 x 112500 = £45000 (TAX)
0% of £12500 = 0 (TAX)
25% of x = 9260
x= £37040 ( kim earned that year)
5 0
3 years ago
P = 3T squared work out the value of p when T = 10
oksian1 [2.3K]

Answer:

P=300

Step-by-step explanation:

P=3T squared

T=10

P=?

P= 3×(10×10)

=3×100

=300

5 0
3 years ago
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