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Bond [772]
3 years ago
14

Which units express heat capacity

Chemistry
2 answers:
vladimir1956 [14]3 years ago
7 0

Answer:

Heat capacity units: J/K

Explanation:

Heat capacity (C) is the amount of heat (Q) required to raise the temperature(T) of a substance by a unit degree.

C = \frac{Q}{T}

It is usually expressed in terms of J/K

Heat capacity is an intensive property i.e. it is not dependent on the amount of the substance. i.e, the amount of heat required to raise the temperature of 1 g of copper per kelvin would be the same as that corresponding to 100 g.

sveta [45]3 years ago
6 0
The heat capacity of a defined system is the amount of heat (usually expressed in calories, kilocalories, or joules) needed to raise the system's temperature by one degree (usually expressed in Celsius or Kelvin). It is expressed in units of thermal energy per degree temperature. To aid in the analysis of systems having certain specific dimensions, molar heat capacity and specific heat capacity can be used. To measure the heat capacity of a reaction, a calorimeter must be used. Bomb calorimeters are used for constant volume heat capacities, although a coffee-cup calorimeter is sufficient for a constant pressure heat capacity.
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Lead has a density of 11.4 g/cm^3. What is the density in kilograms per cubic meter?
Vikentia [17]

The density in kg/m³ = 1.14 x 10⁴

<h3>Further explanation  </h3>

Density is a quantity derived from the mass and volume  

Density is the ratio of mass per unit volume  

With the same mass, the volume of objects that have a high density will be smaller than objects with a smaller type of density  

The unit of density can be expressed in g/cm³ or kg/m³  

Density formula:  

\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}

ρ = density , g/cm³ or kg/m³  

m = mass  , g or kg

v = volume  , cm³ or m³  

A density of Lead : ρ = 11.4 g/cm³

the density in kg/m³ :

\tt 11.4~\dfrac{g}{cm^3}\times \dfrac{kg}{10^3~g}\times \dfrac{cm^3}{10^{-6}~m^3}=\boxed{\bold{1.14\times 10^4~\dfrac{kg}{m^3}}}

8 0
3 years ago
different student is given a 10.0g sample labeled CaBr2 that may contain an inert (nonreacting) impurity. Identify a quantity fr
SCORPION-xisa [38]

Answer:density

Explanation:

3 0
3 years ago
How are the environments of a desert and a tundra different?
klasskru [66]
B. A Tundra is less humid than a desert.

Reasoning: Tundra’s experience low temperatures while deserts experience hot/humid temperatures.
6 0
2 years ago
Rank the following steps involved in preparing a dilute solution from a stock solution in order from first to last.
Serggg [28]

Answer: C - B - A - D

Explanation:

-Obtain a flask that is thoroughly cleaned

-Add the desired amount of stock solution

-Add deionized water until the volume reaches the mark on the flask.

- Cap the flask and invert several times to thoroughly mix the solution.

5 0
3 years ago
5. What is the final "Celsius" temperature if 2.40 L of gas at 30.5 C is cooled until the volume reaches 1.00 L at constant pres
slega [8]

Answer:

Final temperature of the gas = -146.63 °C

Explanation:

At constant pressure, volume and temperature of the gases are related as:

\frac{V_1}{T_1}=\frac{V_2}{T_2}

Where,

V1 = Initial volume = 1.00 L

V2 = Final volume = 2.40 L

T1 = Initial temperature = 30.5 °C = 30.5 + 273.15 = 303.65 K

Now, substitute the values in the above equation,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

\frac{2.40\;L}{303.65}=\frac{1.00\;L}{T_2}

T_2=\frac{1.00\times 303.65}{2.40}

T2 = 126.52 K

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

T( °C) = T(K) - 273.15

          = 126.52 - 273.15 = -146.63 °C

7 0
3 years ago
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