Answer:
a. True
Explanation:
The bonds between atoms are called chemical bonds. These bonds act as though they were a spring holding these atoms together.
When the atoms in a given bond are compressed by decreasing their distance of separation from their equilibrium position, a force provided by the bond tries to prevent these atoms from getting too close than usual. If on the other hand the atoms are stretched by increasing their distance of separation from their equilibrium position, a force provided by the bond tries to pull these atoms together again. This behaviour of the bond is what makes it to be considered as being similar to a spring.
Answer:
Doubled.
Explanation:
The relationship between the temperature and the volume of a gas at a constant pressure can be described using Charles' law:
That means that the temperature and the volume of a gas are directly proportional: The higher the temperature, the higher the pressure. If one of those factors is increased twofold, the other one will be increased twofold as well.
Answer:
(a) SeF₄
(b) OF₂
(c) N₂O
(d) PCl₃
Explanation:
Write the formula for each compound.
(a) selenium tetrafluoride. According to the name, this compound has 1 atom of Se and 4 atoms of F. The resulting formula is SeF₄, in which Se has the oxidation number 4+ and F has the oxidation number 1-.
(b) oxygen difluoride. According to the name, this compound has 1 atom of O and 2 atoms of F. The resulting formula is OF₂, in which the oxidation number of O is 2+ and the oxidation number of F is 1-.
(c) dinitrogen monoxide. According to the name, this compound has 2 atoms of N and 1 atom of O. The resulting formula is N₂O, in which the oxidation number of N is 1+ and the oxidation number of O is 2-.
(d) phosphorus trichloride. According to the name, this compound has 1 atom of P and 3 atoms of Cl. The resulting formula is PCl₃, in which the oxidation number of P is 3+ and the oxidation number of Cl is 1-.
Answer:
yes because tissues take long to survive the aeedlings
Answer:
39.72 g
Explanation:
Given data:
Mass of CsF = 15.2 g
Mass of XeF₆ = 260 g
Mass of Cs[XeF₇] = ?
Solution:
Chemical reaction:
CsF + XeF₆ → Cs[XeF₇]
Number of moles of CsF:
Number of moles = mass/ molar mass
Number of moles = 15.2 g/151.9 g/mol
Number of moles = 0.1 mol
Number of moles of XeF₆ :
Number of moles = mass/ molar mass
Number of moles = 260 g/245.28 g/mol
Number of moles = 1.06 mol
Now we will compare the moles of Cs[XeF₇] with both reactants.
CsF : Cs[XeF₇]
1 : 1
0.1 : 0.1
XeF₆ : Cs[XeF₇]
1 : 1
1.06 ; 1.06
Number of moles of Cs[XeF₇] produce by CsF are less so it will limiting reactant and limit the yield of Cs[XeF₇].
Mass of Cs[XeF₇]:
Mass = number of moles × molar mass
Mass = 0.1 mol × 397.2 g/mol
Mass = 39.72 g
