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<span>NO2 weighs 46.005 grams per mol. There are 6.02x10^23 molecules in a mol. In the given sample of 189.5 grams, there are 4.12 mols. This means that there are 2.48x10^24 molecules of NO2 in the given sample.</span>
Answer: N3 H12 P O3
Explanation:
From the question :
N = 31.57% H = 9.10% P = 23.27%
O= 36.06%
Divide each of the element by their respective relative atomic masses.
N = 31.57 / 14 = 2.26
H = 9.10/ 1 = 9.10
P = 23.27 / 31= 0.750
O =36.06 / 16 = 2.25
Divide each answer by the lowest of them all, we then have:
N = 2.26/ 0.750 = Approx = 3
H = 9.10 / 0.750 = Approx = 12
P = 0.750/ 0.750= 1
O = 2.25 / 0.750 = Approx = 3
The empiral formula is
N3 H12 P O3