For Jacob's birthday, a basketball is wrapped in wrapping paper with no overlaps. The ball has a volume of 288π in3. What is the

Question

arsen [322]

3 years ago

9

For Jacob's birthday, a basketball is wrapped in wrapping paper with no overlaps. The ball has a volume of 288π in3. What is the

area of the wrapping paper (in terms of π)?

Mathematics

2 answers:

Dimas [21] · Answer 1 · 2022-03-06T18:56:00+03:00

Dimas [21]3 years ago

7 0

288π×3=2714.33605 hope this helps

Leya [2.2K] · Answer 2 · 2022-03-06T21:18:32+03:00

To find the area of the wrapping paper you have to find the serface area of the ball
you have the volume so you have to find the raduis using the formula
r=3(v/4pi)^1/3
r=3(288pi/4pi)^1/3
r=3(72)^1/3
r=216^1/3
r=6
then the surface area of the sphere
SA=4pi x r^2
SA=4pi x 6^2
SA=4pi x 36
SA=144pi