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3 years ago

An atom with 5 protons, 6 neutrons, and 5 electrons has an atomic mass of _____ amu. (Enter a whole number.)

Chemistry

2 answers:

yarga [219]3 years ago

8 0

an atom with 5 protons, 6 neutrons and 5 electrons has an atomic mass of 11 amu

explanation

Atomic mass is also referred to as mass number.

atomic mass is equivalent to total number of protons and neutrons.

An atoms with 5 protons, 6 neutrons and 5 electron has a atomic mass of 11 because the total number of protons and neutrons =11

beks73 [17]3 years ago

3 0

Your answer would be 11 AMU.

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The chemical symbol for a calcium ion is ca2 . what does the 2 symbolize

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2 stands for valency of ca ion

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3 years ago

The book procedure calls for 2,5-dimethylhexane-2,5-diol and concentrated hydrochloric acid to be shaken in a reaction vial. Whi

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Answer:

E) All of the above.

Explanation:

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3 years ago

Scientists in a lab are working with two different samples of the element mercury. They know that the different samples are diff

NeTakaya

Answer:

the mass number

Explanation:

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3 years ago

What is the correct name for the ionic compound Ca2P5

maks197457 [2]

Answer:

It is calcium phosphide.

Explanation:

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3 years ago

Read 2 more answers

A slurry of flakes soybeans weighing a total of 100 kg contains 75 kg of inert solids and 25 kg of solution with 10 wt% oil and

lubasha [3.4K]

Answer:

the amounts and compositions of the overflow V1 and underflow L1 leaving the stage are 75kg and 125kg respectively.

Explanation:

Let state the given parameters;

Let A= solvent (hexane)

B= solid(inert soiid)

C= solvent(oil)

$F_{solution}$ = mass of solvent + mass of oil (i.e A+C)

Feed Phase:

Total feed (i.e slurry of flakes soybeans)= 100kg

B= mass of solid =75 kg

F= mass of solvent + mass of oil (i.e A+C)

= 25kg

Mass ratio of oil to solution $Y_{F}$ = $\frac{Mass C}{Mass (A+C)}$

mass of oil (C) =25 × 0.1 wt = 2.5kg

mass of hexane in feed = 25 × 0.9 =22.5kg + 2.5 =25kg

therefore $Y_{F}$ = $\frac{2.5}{25}$

= 0.1

mass ratio of solid to solution $Y_{A}$ = $\frac{Mass A}{Mass (A+C)}=[tex]\frac{75}{25}$

Solvent Phase:

C= Mass of oil= 0(kg)

A= Mass of hexane = 100kg

mass of solutions = A+C = 0+100kg

solvent= 100kg

Underflow:

underflow = L₁ = (unknown) ???

L₁ = E₁ + B

the value of N for the outlet and underflow is 1.5 kg

i.e N₁ = $\frac{mass B}{mass(A+C)}$

solution in underflow E₁ = Mass (A+C)

Overflow:

Overflow = V₁ = (unknown) ???

solution in overflow V₁ = Mass (A+C)

This is because, B = 0 in overflow

Solid Balance: (since the solid is inert, then is said to be same in feed & underflow).

solid in feed = solid in underflow = 75

75= E₁ × N₁

75 = E₁ × 1.5

E₁ = 50kg

Underflow L₁ = E₁ × B

= 50 + 75

=125kg

The Overall Balance: Feed + Solvent = underflow + overflow

100 + 100 = 125 + V₁

V₁ = 75kg

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