The peaks at 3300 cm-1 and 2200 cm-1 are due to terminal alkyne group (triple bond between two carbons) and triple bonded C-H stretching
So
The answer is : terminal alkyne
Another peak near 3430 cm-1 must be due to an -OH group
so the answer is : alcohol
<h3>Answer:</h3>
1.0 × 10⁻⁶ M (Option-A)
<h3>Solution:</h3>
Data Given:
pH = 6
[H⁺] = ?
Formula Used:
As we know pH is given as,
pH = -log [H⁺]
and,
[H⁺] = 10^-pH ----- (1)
Putting value of pH in eq. 1,
[H⁺] = 10⁻⁶ ∴ 10 = Antilog
[H⁺] = 1.0 × 10⁻⁶ M
The first one is abundant
I think it is A. ability to oxidize :)
Answer:
1. I shifts toward products and II shifts toward reactants.
Explanation:
Hello,
In his case, since the reaction I) is endothermic (positive ∆H°) and the reaction II) is exothermic (negative ∆H°):
- In the first case, the energy is understood as a reactant, so if the temperature increases, heat is added so the reaction will shift rightwards (towards products).
- In the second case, the energy is understood as a product, so if the temperature increases, heat is added so the reaction will shift leftwards (towards reactants).
Therefore, the answer is:
1. I shifts toward products and II shifts toward reactants.
Best regards.
