Question

2c4H10 +13O2 —>8CO2+10H2O to find how many moles of oxygen would react with 4.3 mol C4H10

Answer 1

Answer:

$\large\boxed{\text{28 mol of O _{2} }}$

Explanation:

             2C₄H₁₀ + 13O₂ ⟶ 8CO₂ + 10H₂O

n/mol:      4.3  

13 mol of O₂ react with 2 mol of 2C₄H₁₀

$\text{Moles of O}_{2} = \text{4.3 mol C _{4} H _{10} } \times \dfrac{\text{13 mol O}_{2}}{\text{2 mol C _{4} H _{10} }} = \textbf{28 mol O}_{2}\\\\\text{The reaction requires \large\boxed{\textbf{28 mol of O _{2} }} }$