<u>Answer:</u>
<u>For a:</u> The standard Gibbs free energy of the reaction is -347.4 kJ
<u>For b:</u> The standard Gibbs free energy of the reaction is 746.91 kJ
<u>Explanation:</u>
Relationship between standard Gibbs free energy and standard electrode potential follows:
............(1)
The given chemical equation follows:
<u>Oxidation half reaction:</u> ( × 2)
<u>Reduction half reaction:</u>
We are given:
Putting values in equation 1, we get:
Hence, the standard Gibbs free energy of the reaction is -347.4 kJ
The given chemical equation follows:
<u>Oxidation half reaction:</u> ( × 6)
<u>Reduction half reaction:</u>
We are given:
Putting values in equation 1, we get:
Hence, the standard Gibbs free energy of the reaction is 746.91 kJ
no the best source is blood.
Answer:
When iron is heated in air it reacts with oxygen to form the compound iron oxide. Iron is a solid and oxygen is a gas. 5 Draw diagrams to show how the atoms are arranged in iron, oxygen and iron oxide in the circles below their names. Use different colours for the iron atoms and the oxygen atoms.
Explanation:
Answer:
a. 581.4 Pa
b. 3.33x10⁻⁴ mol/L
c. 3.49x10⁻⁴ mol/L
d. 0.015 g/L
Explanation:
a. By the Raoult's Law, the partial pressure of a component of a gas mixture is its composition multiplied by the total pressure, so:
pA = 0.9532*6.1
pA = 5.81452 mbar
pA = 5.814x10⁻³ bar
1 bar ----- 10000 Pa
5.814x10⁻³ bar--- pA
pA = 581.4 Pa
b. Considering the mixture as an ideal gas, let's assume the volume as 1,000 L, so by the ideal gas law, the total number of moles is:
PV = nRT
Where P is the pressure (610 Pa), V is the volume (1 m³), n is the number of moles, R is the gas constant (8.314 m³.Pa/mol.K), and T is the temperature.
n = PV/RT
n = (610*1)/(8.314*210)
n = 0.3494 mol
The number of moles of CO₂ is (V = 0.9532*1 = 0.9532 m³):
n = PV/RT
n = (581.4*0.9532)/(8.314*210)
n = 0.3174 mol
cA = n/V
cA = 0.3174/953.2
cA = 3.33x10⁻⁴ mol/L
c. c = ntotal/Vtotal
c = 0.3494/1000
c = 3.49x10⁻⁴ mol/L
d. The molar masses of the gases are:
CO₂: 44 g/mol
N₂: 28 g/mol
Ar: 40 g/mol
O₂: 32 g/mol
CO: 28 g/mol
The molar mass of the mixture is:
M = 0.9532*44 + 0.027*28 + 0.016*40 + 0.0008*28 = 43.36 g/mol
The mass concentration is the molar concentration multiplied by the molar mass:
3.49x10⁻⁴ mol/L * 43.36 g/mol
0.015 g/L
Answer:
Blue color of iodine-starch complex is disappear upon hysrolysis
Explanation:
Starch:
Starch is a polysaccharide
it is energy reservoir.
starch is made of monomers of glucose in a chain form.
The simplest form of starch is linear polymer amylose.
Iodine Test:
In this test iodine solution added to the solution to check the presence of starch.
Iodine solution = elemental iodine + KI
Result of Iodine Test:
when the iodine solution (I₃⁻) is added to a solution it show two types of result.
if the starch is present this I₃⁻ form a complex with amylose chain of starch and impart a dark blue color.
if starch is not present then the color will be orange or yellow.
Hydrolysis of Starch:
Hydrolysis of starch is carried out by an enzyme, this enzyme break down the starch into simpler sugar molecule.
So,
When the hydrolysis of starch occur the starch convert to glucose. Then the blue color of starch and iodine complex formed during iodine test is disappear that will be the indication of hydrolysis of starch.