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kiruha [24]
3 years ago
13

2.303 3-5.05x10-3 1 | - 1 T2298

Chemistry
1 answer:
bekas [8.4K]3 years ago
6 0

Answer:

230,294.9 I think it's fine just try your past or ask teacher help

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All of the following, except a _ might be studied by a microbiologist.
timurjin [86]
It would be a human egg cell. Microbiologists study microscopic organisms that cause infections, including viruses, bacteria, and fungi+algae
8 0
3 years ago
What does the Coriolis effect describe
zzz [600]

Answer:

The Coriolis effect describes the pattern of deflection taken by objects not firmly connected to the ground as they travel long distances around Earth. ... The key to the Coriolis effect lies in Earth's rotation. Specifically, Earth rotates faster at the Equator than it does at the poles

Explanation:

Hope it helps

6 0
3 years ago
In a laboratory experiment, John uses a mesh to separate soil particles from water. Which technique of separation is he using?
Aneli [31]
Salutations!

<span>In a laboratory experiment, John uses a mesh to separate soil particles from water. Which technique of separation is he using?

The technique that John is using is the filtration technique. Filtration is a technique to separate the solid which is insoluble from the liquid. For instance: Sand and water, sand is insoluble, thus it stays in the filter paper, while the water proceeds through the filter paper.

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3 0
3 years ago
What is the mass of 0.50 mole of copper?<br> 63.5 grams<br> O 32 grams<br> 3.2 grams<br> 2.18 grams
Amanda [17]

Answer:

32 g Cu

Explanation:

1 mol Cu    -> 63.5 g

0.5 mol Cu ->x

x=(0.5 mol *63.5 g)/1 mol      x= 32 g Cu

3 0
3 years ago
White vinegar is a 5.0% by mass solution of acetic acid in water. If the density of white
Alex_Xolod [135]

The pH = 2.41

<h3>Further explanation</h3>

Given

5.0% by mass solution of acetic acid

the density of white  vinegar is 1.007 g/cm3

Required

pH

Solution

Molarity of solution :

\tt M=\dfrac{\%mass\times \rho\times 10}{MW~acetic~acid}\\\\M=\dfrac{5\times 1.007\times 10}{60}\\\\M=0.839

Ka for acetic acid = 1.8 x 10⁻⁵

[H⁺] for weak acid :

\tt [H^+]=\sqrt{Ka.M}

Input the value :

\tt [H^+]=\sqrt{1.8\times 10^{-5}\times 0.839}\\\\(H^+]=0.00388=3.88\times 10^{-3}\\\\pH=3-log~3.88=2.41

7 0
3 years ago
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