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madam [21]
3 years ago
11

A bowling ball is dropped off the top of the Eiffel Tower. If the Eiffel Tower is 300 meters

Physics
1 answer:
patriot [66]3 years ago
5 0

Answer:

7.82 s

Explanation:

Given:

Δy = 300 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

(300 m) = (0 m/s) t + ½ (9.8 m/s²) t²

t = 7.82 s

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3 years ago
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Una niña está empujando un baúl. El PESO del baúl es de 230 N y el roce es de 50 N, la niña sólo logra ejercer una fuerza de 30
Gre4nikov [31]

Answer:

Su padre necesita aplicar una fuerza de 20 newtons en la misma dirección que la fuerza aplicada por su hija.

Explanation:

Asúmase que el baúl se mueve en una superficie horizontal. La fuerza de rozamiento dada por el problema es la fuerza de rozamiento estático máximo, se requiere una fuerza externa antiparalela a la fuerza de rozamiento estático máximo para que el baúl se empiece a mover. La ecuación de equilibrio de fuerzas horizontales sobre el baúl es:

\Sigma F = P - f = 0

Donde:

P - Fuerza externa aplicada sobre el baúl, medida en newtons.

f - Fuerza de rozamiento estático máximo, medida en newtons.

Se despeja la fuerza externa:

P = f

Si f = 50\,N, entonces:

P = 50\,N

Si la niña solo logra ejercer una fuerza de 30 newtons, su padre necesita aplicar una fuerza de 20 newtons paralela a aquella fuerza.

5 0
3 years ago
Chuck drove 35mi from Austin to San Marcos in 40min, stopped 30min for a hamburger, and then drove 45mi to San Antonio in 50min.
Effectus [21]

Answer:

his average speed was 40 miles per hour

5 0
3 years ago
g An object with mass m=2 kg is completely submerged, and tethered, to the bottom of a large body of water. If the density of th
Anit [1.1K]

Answer:

The tension in the rope is 20 N

Solution:

As per the question:

Mass of the object, M = 2 kg

Density of water, \rho_{w} = 1000\ kg/m^{3}

Density of the object, \rho_{ob} = 500\kg/m^{3}

Acceleration due to gravity, g = 10\ m/s^{2}

Now,

From the fig.1:

'N' represents the Bouyant force and T represents tension in the rope.

Suppose, the volume of the block be V:

V = \frac{M}{\rho_{ob}}              (1)

Also, we know that Bouyant force is given by:

N = \rho_{w}Vg

Using eqn (1):

N = \rho_{w}\frac{M}{\rho_{ob}}g

N = 1000\frac{2}{500}\times 10 = 40\ N

From the fig.1:

N = Mg + T

40 = 2(10) + T

T = 40 - 20 = 20 N

N = \rho_{w}Vg

3 0
3 years ago
Any one any kind of clue on this please need help
devlian [24]

I honestly think it is B, if not I'm sorry for the incorrect answer, but B seems to be the only one to make sense

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