Here is the solution based on the given problem above.
Given: Area of the piece of paper = 84 square inches
Width = 10 1/2 or 10.5 inches long
? = length of the piece of paper
To find the area of an object, the formula would be A= L x W
Now, let's substitute the given values above
84in2 = L(10.5in)
Now, divide both sides with 10.5 and we get 8.
L = 8 inches.
Therefore, the length of the paper is 8 inches.
Hope this solution helps.
First combine like terms (-9n-3n=-12n)
Then, subtract 6n on both sides (to get rid of the 6n) = -18n
Then, add 8 to both sides (does not matter) = 0
Finally divide (answer is 0)
Answer:
The number of people needed is
Step-by-step explanation:
From the question we are told that
The population proportion is 
The margin of error is 
From the question we are told the confidence level is 90% , hence the level of significance is
=>
Generally from the normal distribution table the critical value of
is
Generally the sample size is mathematically represented as
![n =[ \frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * p(1-p)](https://tex.z-dn.net/?f=n%20%3D%5B%20%5Cfrac%7BZ_%7B%5Cfrac%7B%5Calpha%20%7D%7B2%7D%20%7D%7D%7BE%7D%20%5D%5E2%20%2A%20p%281-p%29)
=> ![n =[ \frac{1.645 }{0.03} ]^2 * 0.65(1-0.65)](https://tex.z-dn.net/?f=n%20%3D%5B%20%5Cfrac%7B1.645%20%7D%7B0.03%7D%20%5D%5E2%20%2A%200.65%281-0.65%29)
=>
Answer:
1
Step-by-step explanation:
5/9 = 0.5555555
The smallest sequence of repeating digits in the decimal equivalent of 5/9
0.5
0.5 + 0.05
0.5 + 0.05 + 0.005
0.5 + 0.05 + 0.005 + 0.0005
Hence, the number of digit in the smallest sequence of repeating decimal is 1
5/9 = 0.5....
<u>Answer</u>:- No.
<u>Explanation</u> :-
<u>Substitute these numbers in pythagoras theorem to check if the set of numbers is a pythagorean triplet.</u>
<u>Pythagoras theorem</u> :- sq. of hypotenuse (longest side) is equal to the sum of sq.s of other two sides.
<u>Here</u>,
hypotenuse = 12 (as it is the longest side)
and other two sides are 6 and 9.
----> 6^2 + 9^2 = 12^2
----> 36 + 81 = 144
----> 117 = 144
Since, LHS is not equal to RHS, this set of numbers is not a pythagorean triplet.