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Gemiola [76]
3 years ago
10

Put 4/9 3/8 2/5 in order from least to greatest

Mathematics
1 answer:
Setler79 [48]3 years ago
5 0

Answer:3/8,2/5,4/9

Step-by-step explanation:

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its x: x< -3

Step-by-step explanation:

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PLEASE ANSWER QUICK<br><br> What is the unit rate for the ratio 96:8
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12:1

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96/8 = 12

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BRAINLIEST if correct
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Okay so median is the number in the middle and mean is when you add them all up and divide by how many numbers there are 

<span>20,28,35,40,132 

So 35 is the median 
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18/34 as a reduced fraction
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I like to reduce everything by half if I don't already know the answer.

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3 0
3 years ago
The number N of cars produced at a certain factory in 1 day after t hours of operation is given by Upper N (t )equals 800 t minu
Elden [556K]

Answer:

The cost C as a function of t is C(t) = 30,000 + 6,400,000 t - 40,000 t²

Step-by-step explanation:

The function N(t) = 800 t -  5t², represents the number of cars produced at a time t hours in a day, where 0 ≤ t ≤ 10

The function C(N) = 30,000 + 8,000 N, represents the cost C​ (in dollars) of producing N cars

We need to find The cost C as a function of the time t

That means Substitute N in C by its function by other word find the composite function (C о N)(t)

∵ C(N) = 30,000 + 8,000 N

∵ N(t) = 800 t - 5 t²

- Substitute N in C by 800 t - 5 t²

∴ C(N(t)) = 30,000 + 8000(800 t - 5 t²)

- Multiply the bracket by 8000

∴ C(N(t)) = 30,000 + 8000(800 t) - 8000(5 t²)

∴ C(N(t)) = 30,000 + 6,400,000 t - 40,000 t²

- C(N(t) = C(t)

∴ C(t) = 30,000 + 6,400,000 t - 40,000 t²

The cost C as a function of t is C(t) = 30,000 + 6,400,000 t - 40,000 t²

5 0
3 years ago
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