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max2010maxim [7]
3 years ago
6

Would it be “A” or “C”?

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
7 0

Answer:

Tagging Problem for future searchers

Step-by-step explanation:

Which expression represents the statement "four less than the product of three and a number"?

A) 4-3n

B) 4-n/3

C) 3n-4

D) n/3-4

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If cscx=3, 90 degrees
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4 0
3 years ago
Rex weighed 80 pounds a year ago. Now he weighs 92 pounds. What is the percent increase in his weight?
bezimeni [28]
So base on the question, that states the weight of Rex from last year to the present, and find its rate if change or percentage of change. To calculate the percentage you must first subtract the said weight in the present to its past then divide it by its past weight then multiply it by 100. So the percentage would be 15 %. I hope this would help 

8 0
3 years ago
mary will spin the spinner below 150 times. about how many times should mary expect the spinner to land on a number greater than
irga5000 [103]

Answer:

56 times (This is still assuming 1 isnt an option)

Step-by-step explanation:

0,2,3,4,5,6,7,8

There are 8 options, 3 of which are greater than 5

3/8

3/8 = x/150

3*150 = 450

8 * x = 8x

8x = 450

450/8  = 56.25

56 times

-- Gage Millar

5 0
2 years ago
A raft traveled 24 miles upstream on a river in 6 hours. The return trip took the raft 3 hours. What is the rate of the raft in
Lynna [10]

Answer:

                                                                   

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
PLEASE HELP ME THIS.. I REALLY NEED<br> HELP
Colt1911 [192]

9514 1404 393

Answer:

  5 hours

Step-by-step explanation:

A quick way to look at this is to compare the difference in hourly charge to the difference in 0-hour charge.

The first day, the charge is $3 more than $12 per hour.

The second day, the charge is $12 less than $15 per hour.

The difference in 0-hour charges is 3 -(-12) = 15. The difference in per-hour charges is 15 -12 = 3. The ratio of these is ...

  $15/($3/h) = 5 h

The charges are the same after 5 hours.

__

If you write equations for the charges, they will look like ...

  y1 = 15 + 12(x -1)

  y2 = 3 + 15(x -1)

Equating these charges, we have ...

  15 +12(x -1) = 3 + 15(x -1)

  12x +3 = 15x -12 . . . . . . . . eliminate parentheses

  15 = 3x . . . . . . . . . . add 12-12x

  x = 15/3 = 5 . . . . . . divide by 3

You might notice that the math here is very similar to that described in words, above.

The charges are the same after 5 hours.

6 0
3 years ago
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