Answer:
Laplace transforms turn a Differential equation into an algebraic, so we can solve easier.
y'= pY-y(0)
y"=p²Y - py(0)- y'(0)
Substituting these in differential equation :
p²Y -py (0) -y' (0)-6(pY-y(0)) + 13Y
Substituting in the initial conditions given , fact out Y, and get:
Y( p²-6p+13) = -3
Y=-3/ p²-6p+13
now looking this up in a table to Laplace transformation we get:
y=-3/2.e³т sin(2t)
for the last one, find the Laplace of t∧2 . which is 2/p³
pY - y(0)+ 5Y= 2/p³
Y= 2/p³(p+5)
Taking partial fractions:
Y=-2/125(p+5) + 2/125p - 2/25p² + 2/5p³
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Answer:
2 and 20
Step-by-step explanation:
First how can we get rid of the fraction?
We can multiply -1/2 by 2 to get -1
Next what number do we multiply to get from -1 to -20?
-1x = -20
divide both sides by -1
x = 20
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We cannot answer since we do not have the picture or diagram.
Answer: Our required probability would be 0.70.
Step-by-step explanation:
Since we have given that
Number of players = 14
Number of players have recently taken a performance enhancing drug = 3
Number of players have not recently taken a performance enhancing drug = 14-3=11
Number of members chosen randomly = 5
We need to find the probability that at least one of the tested players is found to have taken a performance enhancing drug.
P(Atleast 1) = 1 - P(none is found to have taken a performance enhancing drug)
So, P(X≥1)=1-P(X=0)
Hence, our required probability would be 0.70.
Answer:
3
(
3
)
+
6
(
2
)
+
2
=
2
(
3
)
+
3
(
2
)
+
5
Step-by-step explanation:
