The compression factor based on the information given is 0.083.
<h3>How to calculate the compression factor?</h3>
The way to calculate the compression factor goes this:
V(ideal) = RT/P
= (0.0821 × 250)/15
= 1.368
V(real) will be:
= V(ideal)/12
= 1.368/12 = 0.114
The compression factor will be:
= 1.368/(12 × 1.368)
= 0.083
Therefore, the compression factor is 0.083.
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Hello!
On the periodic table, as we go down the periodic table, the ionization energy decreases, but as we go across the periodic table (left to right), the ionization increases.
On the periodic table, lithium (Li) is located in column one, beryllium (Be) is located in column two, and (B) boron is located in column 13. As stated above, when we go across the periodic table (left to right), the ionization increases.
Therefore, the element with the highest ionization energy is Boron, or symbol B on the period table.
Manganese has 25 electrons and is a transition element
Answer:
Following are the solution to these question:
Explanation:
Calculating the mean:


Calculating the standardn:

Please find the correct equation in the attached file.

For point a:

For point b:

For point c:

It is calculated by using the slope value that is
. The slope value
is ambiguous.
Answer:
Phase changes that require a loss in energy are condensation and freezing.
Explanation: