Answer:
There is 5720 J of heat released.
Explanation:
Step 1: Data given
Molar mass of CH6N2 = 46.07 g/mol
The heat of combustion of methylhydrazine is −1.30 × 103 kJ/mol
Mass of methylhydrazine = 202.7 grams
Step 2: Calculate number of moles
Moles CH6N2 = mass of CH6N2 / Molar mass CH6N2
Moles CH6N2 = 202.7 grams / 46.07 g/mol
Moles CH6N2 = 4.4 moles
Step 3: Calculate heat released when 202.7 grams of CH6N2 is burned
q = 1300 J/mol * 4.4 moles
q = 5720 J
(Since there is heat released, ΔH = negative)
There is 5720 J released.
Its D as A, B and C are physical properties of water
Answer:
306.43 K
Explanation:
- Use Charle's law and rearrange formula (V1/T1=V2/T2)
- Hope this helped! Let me know if you would like me to show you step-by-step how to do these types of problems.
Answer:
pOH = 13.246
Explanation:
pH = -log[H+]
[H+] = [HBr] porque HBr es un acido fuerte.
pH = -log(0.176) = 0.754
pH + pOH = 14
pOH = 14 - 0.754 = 13.246
An ionic compound is composed of ionic bonds that are formed by transfer of electrons from one atom to the other. The atom that loses electrons acquires a positive charge (cation) while that which gains electrons acquires a negative charge.
In the case of sodium chloride; Sodium Na has 1 electron in its outer orbital while Chlorine Cl has 7 electrons. Thus, Cl requires 1 electron to complete its octet. This electron is donated by Na.
Thus, NaCl is essentially, Na⁺Cl⁻
Ans D) Chlorine becomes an anion by gaining an electron from sodium