Question

A kettle of water is at 14.5°C. Its temperature is then raised to 50.0°C by supplying it with 5,680 joules of heat. The specific heat capacity of water is 4.186 joules/gram degree Celsius. What is the mass of water in the kettle? Express your answer to three significant figures. The mass of the water in the kettle is grams.

Answer 1

Answer:- 38.2 g.

Solution:- The equation used for solving this type of calorimetry problems is:

$q=mc\Delta T$

where, q is the heat energy, m is mass, c is specific heat and delta T is the change in temperature.

Water temperature is increasing from 14.5 degree C to 50.0 degree C.

$\Delta T=50.0-14.5$  = 35.5 degree C

q is given as 5680 J and specific heat value is $4.186\frac{J}{g.^0C}$ .

The equation could be rearranged for m as:

$m=\frac{q}{c*\Delta T}$

Let's plug in the values in it:

$m=\frac{5680}{4.186*35.5}$

m = 38.2 g

So, the mass of water in the kettle is 38.2 g.

Answer 2

Answer: The mass of the water in the kettle is 38.2 g