The power used by Alex to drag the log across the yard is determined as 2,656 W.
<h3>Mass of the log</h3>
The mass of the log is calculated as follows;
W = mg
m = W/g
m = (400)/9.8
m = 40.82 kg
<h3>Velocity of the log</h3>
K.E = ¹/₂mv²
v² = 2K.E/m
v² = (2 x 900)/(40.82)
v² = 44.096
v = 6.64 m/s
<h3>Power used by Alex</h3>
P = Fv
P = 400 x 6.64
P = 2,656 W
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Answer:
-Growth of plants on the rock.
-Temperature and pressure changes in nature.
-Freezing and thawing of water in cracks of the rock.
-Formation of salt crystals within the rock.
-Burrowing by animals.
those are some factors I know
hope this helped you
Answer:
Price ceiling. In order to limit the shortages that naturally result from a price ceiling, the government can do what to certain goods? Ration.
Explanation:
Answer:
T = 82 K
Explanation:
The computation of the final temperature is shown below;
Given that
T_0 denotes the initial temperature of the gas i.e. 74 K
T denotes the final temperature of the gas = ?
n denotes number of moles of monoatomic gas i.e. 1.00 mol
R denotes universal gas constant = 8.314
c denotes the heat capacity at constant volume i.e.
= (1.5) R = (1.5) (8.314)
= 12.5
Q denotes the Amount of heat absorbed i.e 100 J
We know that
Amount of heat absorbed is provided as
Q = n c (T - T_0)
100 = (1) (12.5) (T - 74)
T = 82 K
Answer:
C₂H₆
Explanation:
To obtain molecular formula of the gas, you need to find first its molecular mass.
To find molecular mass you need to obtain moles of gasbecause molecular mass is the ratio between mass of the gas and the volume it occupies.
As at STP, 1 mole of a gas occupies 22.4dm³, 1dm³ of gas are:
1dm³ × (1mol / 22.4dm³) = 004464moles.
Its molecular mass is:
1.35g / 004464moles =
30.24g/mol
Now, if the gas is 80%C and 20%H, its <em>empirical formula (Simplest ratio of atoms in a molecule) </em>is:
80% Carbon × (1mol / 12.01g) = 6.66moles C
20% Hydrogen × (1mol / 1.01g) = 19.8moles H
Ratio of H:C is:
19.8 mol H / 6.66mol C = 3
Thus, you can know you will have 3 moles of Hydrogen per mole of Carbon, CH₃ (It weighs 15.04g/mol)
As the gas weighs 30.24 ≈ 2 CH₃
The molecular formula is:
<h3>C₂H₆</h3>
