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2 years ago

Please answer this question according to the image below

Chemistry

1 answer:

AVprozaik [17]2 years ago

3 0

When we show the structure of a molecule, we see the arrangement of atoms in the molecule.

<h3>Structure of molecules</h3>

The structure of a molecule shows the arrangement of atoms in the molecule.

1) There are 24 carbon atoms in the molecule.

2) There are 30 p- orbitals that are involved in pi bonds in the molecule.

3) We need to add 22 lone pairs of electrons

4) We do not need to add any formal positive charge to the molecule.

Learn more about molecules: brainly.com/question/19922822

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The image represents a typical temperate forest food web. Use the image to answer the following questions(s).

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Answer:

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Explanation:

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3 years ago

Read 2 more answers

If 2.45 g of iron are placed in 1,5 L of 0.25M HCl, how many grams of FeCl2 are obtained? Identify the limiting and excess react

lys-0071 [83]

Answer:

$m_{FeCl_2}=0.652gFeCl_2$

Explanation:

Hello there!

In this case, according to the given information and the chemical reaction, whereby iron and hydrochloric acid react in a 1:2 mole ratio, it is firstly necessary to calculate the moles of iron (II) chloride from each reactant in order to figure out the limiting reactant:

$n_{FeCl_2}=2.45gFe*\frac{1molFe}{55.845gFe}*\frac{1molFeCl_2}{1molFe}=0.0439molFeCl_2\\\\ n_{FeCl_2}=1.5L*0.25\frac{molHCl}{L} *\frac{1molHCl}{36.46gHCl}*\frac{1molFeCl_2}{2molHCl}=0.00514molFeCl_2$

In such a way, we infer the maximum moles of FeCl2 product are yielded by HCl, for which it is the limiting reactant. Finally, we calculate the grams of product by using its molar mass as shown below:

$m_{FeCl_2}=0.00514molFeCl_2*\frac{126.75gFeCl_2}{1molFeCl_2} \\\\m_{FeCl_2}=0.652gFeCl_2$

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7 0

3 years ago

In the reaction, Zn(s) + 2 HCl(aq) --> ZnCl2 (aq)+ H2(g), 25 grams of Zn are reacted with 17.5 g of HCl. How many grams of H2

Gennadij [26K]

Answer:

0.480 g of H₂ are produced, in the reaction.

Explanation:

This is the reaction:

Zn(s) + 2HCl → ZnCl₂ (aq) + H₂ (g)

We havethe mass of both reactants, so we must work with them to find out the limiting reactant and then, determine the amount of H₂ produced.

Let's convert the mass to moles ( mass / molar mass)

25 g / 65.41 g/mol = 0.382 moles Zn

17.5 g / 36.45 g/mol = 0.480 moles HCl

Ratio is 1:2, so 1 mol of Zn react with the double of moles of HCl.

0.382 moles of Zn would need the double of moles to react, so (0.382 .2) = 0.764 moles of HCl. → We only have 0.480 moles, so the acid is the limiting.

Now let's determine the moles of H₂ formed.

Ratio is 2:1, so If i take account the moles I have, I will produce the half of moles of my product.

0.480 moles / 2 = 0.240 moles of H₂ are produced.

To find out the mass, we must multiply mol . molar mass

0.240 mol . 2g/mol = 0.480 g

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3 years ago

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Answer:

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3 years ago