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marta [7]
2 years ago
5

How many moles of hydrogen are needed to produce 8 moles of methane CH4? C + H2-> CH4

Chemistry
1 answer:
Lapatulllka [165]2 years ago
7 0

Answer:

20 mol H₂

General Formulas and Concepts:

<u>Chem</u>

  • Stoichiometry

Explanation:

<u>Step 1: Define</u>

RxN: C + H₂ → CH₄

8 moles CH₄

<u>Step 2: Balance RxN</u>

C + 2H₂ → CH₄

<u />

<u>Step 3: Stoichiometry</u>

8 \ mol \ CH_4(\frac{2 \ mol \ H_2}{1 \ mol \ CH_4} ) = 16 mol H₂

<u>Step 4: Check</u>

<em>We are given 1 sig fig. Follow sig fig rules.</em>

16 mol H₂ ≈ 20 mol H₂

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<u></u>

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Concentration  has a unit of (moles/liter).  When multiplied by the liters of solution used, the result is the number of moles.

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The neutralization of 25.0 ml of sodium hydroxide, NaOH, requires 0.00370 moles of HCl.  The reaction is:

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This balanced equation tells us that neutralization of NaOH with HCl requires the same number of moles of each.  We just determined that the  moles of HCl used was 0.00370 moles.  Therefore, the 25.0 ml solution of NaOH had the same number of moles:  0.00370 moles NaOH.

The 0.00370 moles of NaOH was contained in 25.0 ml (0.025 liters).  The concentration of NaOH is therefore:  

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====

The phosphoric acid problem is handled the same way, but with an added twist.  Phosphoric acid is H3PO4.  We learn the 34.9 ml of the same NaOH solution (0.148M) is needed to neutralize the H3PO4.  But now the acid has three hydrogens that will react.  The balanced equation for this reaction is:

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The moles of NaOH that were used is:

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The 0.00172 moles of H3PO4 was contained in 10.0 ml.  The concentration is therefore:

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<u>Concentration of H3PO4 = 0.172 molar, M</u>

 

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