C. It is a reaction to emotion but not to maintain stability.
2Al + 6HCl ----> 2AlCl3 + 3H2
Hey there !
Molar mass HCl :
HCl =1.01 + 35.45 => 36.46 g/mol
Number of moles ( solute) :
n = m / mm
n = 9.63 / 36.46
n = 0.2641 moles
Therefore :
M = moles / volume ( L )
M = 0.2641 / 1.5
=> 0.176 M
The mass of hematite that contains 8.0×10³ kg of iron is 2.29 × 10⁴ kg.
<h3>What are iron ores?</h3>
Iron ores refers to minerals in which iron occur in combined form found in the earth's crust.
Some ores of iron include:
- hematite,
- magnetite,
- limonite, and
- siderite.
Molar mass of hematite, Fe₂O₃ = 160 g/mol
Molar mass iron = 56 g/mol
Percent mass of iron in hematite = 56/160 = 35%
The mass of hematite that contains 8.0×10³ kg of iron = 8.0 × 10³kg/0.35 = 2.29 × 10⁴ kg.
Therefore, the mass of hematite that contains 8.0×10³ kg of iron is 2.29 × 10⁴ kg.
Learn more about iron ores at: brainly.com/question/4693242
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When you assume that the gas is behaving ideally, the gas molecules are very far from each other that they do not have any intermolecular forces. If it behaves this way, you can assume the ideal gas equation:
PV = nRT, where
P is the pressure
V is the volume
n is the number of moles
R is a gas constant
T is the absolute temperature
When the process goes under constant pressure (and assuming same number of moles),
P/nR = T/V = constant, therefore,
T₁/V₁=T₂/V₂
If V₂ = V₁(1+0.8) = 1.8V₁, then,
T₂/T₁ = 1.8V₁/V₁
Cancelling V₁,
T₂/300=1.8
T₂ =540 K
If you do not assume ideal gas, you use the compressibility factor, z. The gas equation would now become
PV =znRT
However, we cannot solve this because we don't know the value of z₁ and z₂. There will be more unknowns than given so we won't be able to solve the problem. But definitely, the compressibility factor method is more accurate because it does not assume ideality.
