Question

Calculate the inner diameter of the steam tube between the boiler and the high pressure turbine if the average velocity of the steam(state 1) is 60 m/s.
Given is the mass flow rate at 18 kg/s.

Specific volume (v) is 0,036793 m^3/kg

Velocity (V) given as 60 m/s

How do i calculate this ??

Answer 1

Answer:

The inner diameter of the steam tube is 0.1185 m.

Explanation:

$m=\rho \times A\times v=\frac{1}{V}\times A\times v$

m = mass flow rate

$\rho$ = density of the liquid

V=specific volume =$\frac{1}{\rho }$

v = velocity of the liquid

A = area of cross-section

Diameter of the cross-section = d = 2r

Given: m = 18 kg/s, v = 60 m/s,A=?, $V = 0.036793 m^3/kg$

$18 kg/s=\frac{1}{0.036793 m^3/kg}\times A\times 60 m/s$

$A=0.0110379 m^2$

Area of the inner cross section = $\pi r^2=\pi \frac{d^2}{4}$

$\pi \frac{d^2}{4}=0.0110379 m^2$

d = 0.1185 m

The inner diameter of the steam tube is 0.1185 m.