<h3>
Answer:</h3>
2.51 mol Cu
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
1.51 × 10²⁴ atoms Cu
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
- Set up:
![\displaystyle 1.51 \cdot 10^{24} \ atoms \ Cu(\frac{1 \ mol \ Cu}{6.022 \cdot 10^{23} \ atoms \ Cu})](https://tex.z-dn.net/?f=%5Cdisplaystyle%201.51%20%5Ccdot%2010%5E%7B24%7D%20%5C%20atoms%20%5C%20Cu%28%5Cfrac%7B1%20%5C%20mol%20%5C%20Cu%7D%7B6.022%20%5Ccdot%2010%5E%7B23%7D%20%5C%20atoms%20%5C%20Cu%7D%29)
- Multiply/Divide:
![\displaystyle 2.50747 \ mol \ Cu](https://tex.z-dn.net/?f=%5Cdisplaystyle%202.50747%20%5C%20mol%20%5C%20Cu)
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
2.50747 mol Cu ≈ 2.51 mol Cu
18)
a. Ra
d. Ag
19)
a. C
b. Br
c. Mg
20)
a. S
b. Br
c. O
Sorry wasn’t sure about some of them in #18
Hope the notes are helpful.
physical change because even though gas formation was observed, the water was undergoing a state change, which means that its original properties are preserved
Explanation:
The boiling of water is a physical change because the original properties of the water is preserved.
- A physical change is the one that alters the physical properties of matter.
- This kind of change is easily reversible as the water can be cooled back.
- No new kinds of matter is produced in this kind of change .
- The molecules of the matter still retains their property after.
During the boiling of water, intermolecular bonds called hydrogen bonds between the water molecules are broken. This makes the individual molecules free.
Learn more:
Hydrogen bonds brainly.com/question/10602513
#learnwithBrainly
Answer:
174 kPa
Explanation:
Given that,
Initial temperature, T₁ = 25° C = 25+273 = 298 K
Final temperature, T₂ = 225°C = 225 + 273 = 498 K
Initial pressure, P₁ = 104 kPa
We need to find the new pressure. The relation between the temperature and pressure is given by :
![\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}](https://tex.z-dn.net/?f=%5Cdfrac%7BP_1%7D%7BT_1%7D%3D%5Cdfrac%7BP_2%7D%7BT_2%7D)
So,
![P_2=\dfrac{P_1T_2}{T_1}\\\\P_2=\dfrac{104\times 498}{298}\\\\P_2=173.79\ kPa](https://tex.z-dn.net/?f=P_2%3D%5Cdfrac%7BP_1T_2%7D%7BT_1%7D%5C%5C%5C%5CP_2%3D%5Cdfrac%7B104%5Ctimes%20498%7D%7B298%7D%5C%5C%5C%5CP_2%3D173.79%5C%20kPa)
or
P₂ = 174 kPa
So, the new pressure is 174 kPa.
It gives off a certain colour because when the spectrum is combined........I'm not sure if that's write but i think it is.....not 100% sure tho