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3 years ago

Zn(s)+S(s)-ZnS(s) What is the product and physical state

1 answer:

4 0

<span> The Reactants are Zinc (Zn) and Sulfur (S).
The Product is Zinc Sulfide (ZnS).
All of them are solids.
The combined masses of the reactants must be 14 grams, too. Later in Chemistry you'll learn that's not really true, but it is for now.
Hope This Helps:)
</span>

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Which type of bond is formed by the transfer of electrons from one atom to another?

stira [4]

Chemical Bond
because they are chemically bonding

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3 years ago

Aluminum reacts with HCl to produce aluminum chloride and hydrogen gas.

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Answer:

Aluminum Reacts With Hydrochloric Acid To Produce Aluminum Chloride And Hydrogen Gas. 2Al(s) + 6HCl(aq) -> 2AlCl3(aq) + 3H2(g)What Mass Of H2(g) Is Required From The Reaction Of 0.75 G Of Al(s) With Excess Hydrochloric

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3 years ago

Which element has a larger atomic radius than sulfur?

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3 years ago

Consider the reaction of CaC2 and water to produce CaCO3 and NH3 according to the reaction CaCN2 + 3H2O → CaCO3 + 2 NH3 . How mu

xz_007 [3.2K]

Answer:

16.27 g of CaCO3 are produced upon reaction of 45 g CaCN2 and 45 g of H2O.

Explanation:

Ca(CN)2 + 3H2O → CaCO3 + 2 NH3

First of all, let's find out the limiting reactant.

Molar mass Ca(CN)2.

Molar mass H2O: 18 g/m

Moles of Ca(CN)2: mass / molar mass

45 g / 92.08 g/m = 0.488 moles

Moles of H2O: mass / molar mass

45g / 18g/m = 2.50 moles

This is my rule of three

1 mol of Ca(CN)2 needs 3 moles of H2O

2.5 moles of Ca(CN)2 needs (2.5 . 3) / 1 = 7.5 moles

I need 7.5 moles of water, but I only have 0.488. Obviously water is the limiting reactant; now we can work on it.

3 moles of water __ makes __ 1 mol of CaCO3

0.488 moles of water __ makes ___ (0.488 . 1) / 3 = 0.163 moles

Molar mass CaCO3 = 100.08 g/m

Molar mass . moles = mass

100.08 g/m . 0.163 moles = 16.27 g

4 0

3 years ago

Calculate Δ H o for the reaction. CH3OH + HCl → CH3Cl + H2O answer is in kJ/mol .

Nimfa-mama [501]

Answer:

$\Delta H=-28.08 \frac{kJ}{mol}$

Explanation:

Hello,

This types of reactions are likely to be carried out in gaseous phase as it is easier to induce reactions, therefore, for us to compute the change in the enthalpy of this reaction we should write the formation enthalpy of gaseous methanol, hydrogen chloride, methyl chloride and water as -205.1, -92.3, -83.68 and -241.8 kJ/mol respectively. Then, the reaction enthalpy for this reaction is:

$\Delta H=\Delta _fH_{CH_3Cl}+\Delta _fH_{H_2O}-\Delta _fH_{CH_3OH}-\Delta _fH_{HCl}\\\\\Delta H=-83.68\frac{kJ}{mol}-241.8\frac{kJ}{mol}-(-205.1\frac{kJ}{mol})-(-92.3\frac{kJ}{mol} )\\\\\Delta H=-28.08 \frac{kJ}{mol}$

Which accounts for an exothermic chemical reaction.

Regards.

7 0

4 years ago