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Bogdan [553]
3 years ago
15

Please help thank you it’s graphing ratio tables

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
6 0

Answer:Under

Step-by-step explanation:

On top: Under↓

1:$3

2:$6

3:$9

4:$12

5:$15

Hope this helps! 1 Bracelet=$3

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BASEBALL The height of a baseball compared to the
saw5 [17]

Answer:

The shown in the diagram shows that

more the height , lesser will be the distance covered.

Here the point A Is maximum relative.

because if its X value is increased , it's Y value will decreased.

4 0
2 years ago
How do you write the following standard number in expanded notation?
Alex73 [517]
2 × 100 = 2002 × 10 = 202 × 1 = 20 × 0.1 = 07 × 0.01 = 0.07
D. <span>200 + 20 + 2 + 0.07</span>
3 0
3 years ago
Please help i will mark brainliest
Evgen [1.6K]

Answer:

2. \left[\begin{array}{ccc}1&4\\0&3\\\end{array}\right]

3. \left[\begin{array}{ccc}-3&21&60\\-15&9&-45\\\end{array}\right]

4. \left[\begin{array}{ccc}6&-14\\-2&-6\\\end{array}\right]

Step-by-step explanation:

2. This matrix is easy, as it just requires addition.

\left[\begin{array}{ccc}1&4\\0&3\\\end{array}\right]    +     \left[\begin{array}{ccc}0&0\\0&0\\\end{array}\right]   =  \left[\begin{array}{ccc}1&4\\0&3\\\end{array}\right]

3. This matrix requires for the matrices to be multiplied first, then added.

\left[\begin{array}{ccc}9&-15&18\\-27&15&-9\\\end{array}\right]    +     \left[\begin{array}{ccc}-12&36&42 \\12& -6 & -36 \\\end{array}\right]     =   \left[\begin{array}{ccc}-3&21&60\\-15&9&-45\\\end{array}\right]

4.  Here we can add the last 2 matrices to find x.

\left[\begin{array}{ccc}2&-8\\-4&2\\\end{array}\right]   +   \left[\begin{array}{ccc}4&-6\\2&-8 \\\end{array}\right]  = \left[\begin{array}{ccc}6&-14\\-2&-6\\\end{array}\right]

Hope this helps! (Please consider giving brainliest)

4 0
3 years ago
A circle has a circumference of 16π.<br> What is the radius of the circle?
oksian1 [2.3K]
Radius = Circumference / 2π
r = 16π/2π
r = 8

In short, Your Answer would be 8

Hope this helps!
7 0
3 years ago
Read 2 more answers
HELP!!!In the expression 100 a/b, if a is greater than b, which statements are true? b ≠ 0. Select all that apply.
MAXImum [283]

Answer:

\large\boxed{\text{The expression is equal to}\ \sqrt[b]{100^a}}\\\boxed{\text{The expression is greater than 100}}

Step-by-step explanation:

a^\frac{m}{n}=\sqrt[n]{a^m}\\\\\text{True statement:}\\\\100^\frac{a}{b}=\sqrt[b]{100^a}\\\\a>b\to\dfrac{a}{b}>1\to\dfrac{a}{b}=1\dfrac{a-b}{b}\\\\100^\frac{a}{b}=100^{1\frac{a-b}{b}}=100^{1+\frac{a-b}{b}}=100^1\cdot100^\frac{a-b}{b}=100\sqrt[b]{100^{a-b}}\\\\a>b\to a-b>0\to100^{a-b}>1\\\\\text{Therefore}\ 100\sqrt[b]{100^{a-b}}>100

4 0
3 years ago
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