All categories

3 years ago

Which of the following equations is equivalent to 6.87p + 9.2 = -7.056?

Mathematics

1 answer:

Lina20 [59]3 years ago

3 0

Answer:

The answer is the second one 687p + 920 = -705.6

Step-by-step explanation:

The decimal place in each number was shifted right 2 spots

You might be interested in

Find the measure of ∠ 2.<br><br> degrees

miv72 [106K]

$If\ it's\ a\ rhombus,\ then\ |\angle1|=26^o\\\\|\angle1|+|\angle2|+26^o=180^o\ \ /it's\ a\ triangle/\\\\26^o+|\angle2|+26^o=180^o\\52^o+|\angle2|=180^o\ \ \ |subtract\ 52^o\ from\ both\ sides\\\boxed{|\angle2|=128^o}$

7 0

3 years ago

There’s more options but what’s the answer for now

mel-nik [20]

<h3><u>Answer</u><u>:</u><u>-</u></h3>

$\sqrt[3]{125x^{12}y^6}\\\\\\ \to \sqrt[3]{(5x^{4}y^{2})^{^{3}}}\\\\\\ \to 5x^4y^2$

4 0

2 years ago

1.- What is 'a' for this hyperbola?

SpyIntel [72]

Answer:

The standard form of a hyperbola with vertices and foci on the x-axis:

$\dfrac{(x-h)^2}{a^2}-\dfrac{(y-k)^2}{b^2}=1$

where:

center: (h, k)
vertices: (h+a, k) and (h-a,k)
Foci: (h+c, k) and (h-c, k) where the value of c is c² = a² + b²
Slopes of asymptotes: $\pm\left(\dfrac{b}{a}\right)$

The center of the given hyperbola is (0, 0), therefore:

$\implies \dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}=1$

Therefore $(\pm a,0)$ are the vertices. From inspection of the graph, $a=2$ .

Choose two points on the asymptote with the positive slope:

(0, 0) and (4, 6)

Use the slope formula to find the slope:

$\sf slope\:(m)=\dfrac{change\:in\:y}{change\:in\:x}=\dfrac{6-0}{4-0}=\dfrac{3}{2}$

Use the <u>slopes of asymptotes</u> formula, compare with the slope found in part 2:

$\implies \dfrac{b}{a}=\dfrac{3}{2}$

Therefore, $b=3$

Substitute the found values of $a$ and $b$ into the equation from part 1:

$\implies \dfrac{x^2}{2^2}-\dfrac{y^2}{3^2}=1$

$\implies \dfrac{x^2}{4}-\dfrac{y^2}{9}=1$

4 0

1 year ago

Using the triangle below, Find the ratio. Please need help very much appreciate

zmey [24]

Answer/Step-by-step explanation:

✔️Sin 22° = opp/hyp

Opp = 15

Hyp = 40

Sin 22° = 15/40

Simplify

Sin 22° = ⅜

✔️Tan 22° = opp/adjacent

opp = 15

Adjacent = √(40² - 15²) (pythagorean theorem)

Adjacent = √1,375 = 37.1 (nearest tenth)

Tan 22° = 15/37.1

3 0

2 years ago

Ten cards are numbered from 1 to 10 and placed in a box. One card is selected at random and not replaced. Another card is random

Yakvenalex [24]

The probability of picking an even card the first time was 5/10, now that you have 9 cards the probability went down to 4/9.

3 0

3 years ago