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-Dominant- [34]
4 years ago
8

 As a salesperson, you are paid $92 per week plus $4 per sale. This week you want your pay to be at least $200. Write an inequal

ity for the number of sales you need to make, and describe the solutions.
A)92 - 4s ≤ 200; s ≤ 26
B)92 + 4s ≥ 200; s ≥ 26
C)92 - 4s ≤ 200; s ≤ 27
D)92 + 4s ≥ 200; s ≥ 27
Mathematics
1 answer:
KatRina [158]4 years ago
8 0
The equation has to include the total pay that is greater than (≥) $200 AND the $4 per sale has to be added to the $92 weekly rate. The only option that is valid then is D) 92 +4s ≥ 200.

Let's solve for s:

92 + 4s ≥ 200
subtract 92 from both sides

4s ≥ 108
divide both sides by 4

s ≥ 27


ANSWER: D) 92 + 4s ≥ 200; s ≥ 27

Hope this helps! :)
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The first thing we must do is define a variable.

We have then:

x: Linda's speed.

Then, by definition, the time traveled is equal to the distance between the velocity.

We have then:

For Linda:

t = \frac{10}{x}

For Miguel:

t = \frac{14}{x + 4}

Then, since time is the same, then:

\frac{10}{x} = \frac{14}{x + 4}

Clearing Linda's speed we have:

10 (x + 4) = 14x

10x + 40 = 14x

40 = 14x-10x

40 = 4x

x = \frac{40}{4}

x = 10

Then, Miguel's speed is:

x + 4 = 10 + 4 = 14

Answer:

Linda's speed is 10 Km/h

Miguel's speed is 14 Km/h

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3 years ago
What association does the scatter plot show? <br> Answer asap
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2 years ago
A sample size 25 is picked up at random from a population which is normally
Margarita [4]

Answer:

a) P(X < 99) = 0.2033.

b) P(98 < X < 100) = 0.4525

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 100 and variance of 36.

This means that \mu = 100, \sigma = \sqrt{36} = 6

Sample of 25:

This means that n = 25, s = \frac{6}{\sqrt{25}} = 1.2

(a) P(X<99)

This is the pvalue of Z when X = 99. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{99 - 100}{1.2}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033. So

P(X < 99) = 0.2033.

b) P(98 < X < 100)

This is the pvalue of Z when X = 100 subtracted by the pvalue of Z when X = 98. So

X = 100

Z = \frac{X - \mu}{s}

Z = \frac{100 - 100}{1.2}

Z = 0

Z = 0 has a pvalue of 0.5

X = 98

Z = \frac{X - \mu}{s}

Z = \frac{98 - 100}{1.2}

Z = -1.67

Z = -1.67 has a pvalue of 0.0475

0.5 - 0.0475 = 0.4525

So

P(98 < X < 100) = 0.4525

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2 decreased by the sum of m and 8
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Answer:

(m+8) - 2

Step-by-step explanation:

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