5 - substitute the numbers 1-10 for n in (3n-4) and add up all your answers. So (3(1)-4) + (3(2)-4)...
The length of the flagpole is x - 5 yards
<h3>Area of a square</h3>
The formula for calculating the area of the flagpole is expressed as:
A = L²
Given that;
A = x² - 10 + 25
Factorize
A = x² - 5x - 5x + 25
A =(x - 5) - 5(x - 5)
A = (x-5)²
Compare
L = x - 5 yards
Hence the length of the flagpole is x - 5 yards
Learn more on area of a square here: brainly.com/question/13389992
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Answer:
I believe that would be the rate..
Step-by-step explanation:
primero vamos a calcular el lado faltante usando el teorema de pitagoras para poder obtener el lado faltante a
![a=\sqrt[]{hipotenusa^2-cateto^2}](https://tex.z-dn.net/?f=a%3D%5Csqrt%5B%5D%7Bhipotenusa%5E2-cateto%5E2%7D)
![a=\sqrt[]{100^2-85^2}=52.68](https://tex.z-dn.net/?f=a%3D%5Csqrt%5B%5D%7B100%5E2-85%5E2%7D%3D52.68)
a=52.68 m
teniendo el lado faltante podemos calcular las razones trigonometricas
![\sin (55)=\frac{85}{100}=0.85](https://tex.z-dn.net/?f=%5Csin%20%2855%29%3D%5Cfrac%7B85%7D%7B100%7D%3D0.85)
![\cos (55)=\frac{52.68}{100}=0.52](https://tex.z-dn.net/?f=%5Ccos%20%2855%29%3D%5Cfrac%7B52.68%7D%7B100%7D%3D0.52)
![\tan (55)=\frac{85}{52.68}=1.61](https://tex.z-dn.net/?f=%5Ctan%20%2855%29%3D%5Cfrac%7B85%7D%7B52.68%7D%3D1.61)
![\csc (55)=\frac{100}{85}=1.17](https://tex.z-dn.net/?f=%5Ccsc%20%2855%29%3D%5Cfrac%7B100%7D%7B85%7D%3D1.17)
![\sec (55)=\frac{100}{52.68}=1.89](https://tex.z-dn.net/?f=%5Csec%20%2855%29%3D%5Cfrac%7B100%7D%7B52.68%7D%3D1.89)
Answer:
set them equal to each other and solve for x
Step-by-step explanation: