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brilliants [131]
3 years ago
5

55.27 is the same as 55 ____' 12".

Mathematics
1 answer:
choli [55]3 years ago
5 0
<span><span>27100</span>(60)=<span>815</span>=16<span>15</span></span> The 16 is how many minutes you have. If you were not given the seconds, we would have to say that we have a remainder of (1/5) of a minute. Since 1 minute is (1/60), one-fifth of that is (1/300). Now we would need to see how many seconds that gives us. 1 second is (1/3600) of a degree, so we would need to divide (1/300) by (1/3600). Doing this gives us: <span><span><span>1300</span>÷<span>13600</span>=<span>1300</span>(3600)=12</span></span>
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15 of the 25 students Brought their own lunch. What percent of the students brought their own lunch?
bagirrra123 [75]

Answer:

60%

Step-by-step explanation:

1: 15 divided by 25 to get 0.6

2: multiple 0.6 by 100 to get 60%

5 0
3 years ago
What is being constructed based on the markings in the following diagram?
Liula [17]

Answer:

  perpendicular line through a point on a line

Step-by-step explanation:

The circle centered at C seems intended to produce point D at the same distance as point B. That is, C is the midpoint of BD.

The circles centered at B and D with radius greater than BC seems intended to produce intersection points G and H. (It appears accidental that those points are also on circle C. As a rule, that would be difficult to do in one pass.)

So. points G and H are both equidistant from points B and D. A line between them will intersect point C at right angles to AB.

Segment GH is perpendicular to AB through point C (on AB).

6 0
3 years ago
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Find the midpoint and distance between (5,1) and (-15,11)
liq [111]

Answer:

look i think is -5.005 I don't really know but I hope you get it right. Have a good day

4 0
3 years ago
(7^0)^x = 1 what is x ?
Nataly_w [17]
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5 0
3 years ago
Triangle J is shown below. James drew a scaled version of Triangle J using a scale factor of 4 and labeled it
Novay_Z [31]

Answer:

The area of triangle K is 16 times greater than the area of triangle J

Step-by-step explanation:

we know that

If Triangle K is a scaled version of Triangle J

then

Triangle K and Triangle J are similar

If two triangles are similar, then the ratio of its areas is equal to the scale factor squared

Let

z -----> the scale factor

Ak ------> the area of triangle K

Aj -----> the area of triangle J

so

z^{2}=\frac{Ak}{Aj}

we have

z=4

substitute

4^{2}=\frac{Ak}{Aj}

16=\frac{Ak}{Aj}

Ak=16Aj

therefore

The area of triangle K is 16 times greater than the area of triangle J

4 0
2 years ago
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