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Brut [27]
3 years ago
6

Given: AC and BD are diameters. If chord CD is drawn, the measure of angle ACD would be

Mathematics
2 answers:
Elina [12.6K]3 years ago
6 0

Step-by-step explanation:

1=78°

3= 78°

4= 360°- 78° - 78°

= 204° ÷ 2

= 102°

2= 102°

Note that 1+2+3+4=360°

180° - (4)

= 180° - 102°

= 78° ÷ 2

= 39°

ans; angle ACD is 39°

Strike441 [17]3 years ago
3 0

Answer:

39°

Step-by-step explanation:

Both ∠ACD and ∠1 refer to same arc AD

Since ∠1 is central angle, it is the twice the size of ∠ACD,

therefore

  • ∠ACD= ∠1/2= 78°/2= 39°
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