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LekaFEV [45]
3 years ago
11

This is for the roller coaster design packet, I need the graph, I’ll give Brainliest and give a handsome amount of 100 points

Mathematics
1 answer:
frez [133]3 years ago
6 0

Answer:

i am going to work it out

Step-by-step explanation:

i am to ask my mom for help and tell you the answer

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Hi I am sorry if i give you the wrong answer but I think it's three games and 2 movies because 6 times 3 = 18 then 4 times 2 = 8 and 18 + 8 = 26 :)
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One of the altitudes of the parallelogram shown is StartRoot 22.5 EndRoot units. What is the length of the other altitude?
aksik [14]

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the length of the other altitude of the given parallelogram will be 6 units and option B is the correct choice.

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- 1/2 (-5/6 + 1/3) simplified
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-1/2(-5/6+-1/3)
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3 years ago
A salesperson earns $300 per week, plus a 25% commission on each sale made. How much would the salesperson earn if he sold $650
Montano1993 [528]

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$800 = $300 +.05(x), x being the amount that must be sold

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Step-by-step explanation:

5 0
3 years ago
1) Given: circle k(O), ED= diameter ,m∠OEF=32°, m(arc)EF=(2x+10)° Find: x
qaws [65]

1. The major arc ED has measure 180 degrees since ED is a diameter of the circle. The measure of arc EF is (2x+10)^\circ, so the measure of arc DF is

m\widehat{DF}=360^\circ-180^\circ-(2x+10)^\circ=(170-2x)^\circ

The inscribed angle theorem tells us that the central angle subtended by arc DF, \angle DOF, has a measure of twice the measure of the inscribed angle DEF (which is the same angle OEF) so

m\angle DOF=2m\angle OEF=64^\circ

so the measure of arc DF is also 64 degrees. So we have

170-2x=64\implies106=2x\implies\boxed{x=53}

###

2. Arc FE and angle EOF have the same measure, 56 degrees. By the inscribed angle theorem,

m\angle EOF=2m\angle EDF\implies56^\circ=2m\angle EDF\implies m\angle EDF=28^\circ

Triangle DEF is isosceles because FD and ED have the same length, so angles EFD and DEF are congruent. Also, the sum of the interior angles of any triangle is 180 degrees. It follows that

m\angle EFD+m\angle EDF+m\angle DEF=180^\circ\implies\boxed{m\angle EFD=76^\circ}

Triangle OFE is also isosceles, so angles EFO and FEO are congruent. So we have

m\angle EFO+m\angle FEO+m\angle EOF=180^\circ\implies\boxed{m\angle EFO=62^\circ}

7 0
3 years ago
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