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4 years ago

PLEASE HELP ME

Physics

2 answers:

Damm [24]4 years ago

7 0

Answer:

Mixture

Explanation:

I took the test and got it right

Snowcat [4.5K]4 years ago

6 0

Answer:

Compound.

Explanation:

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A positron has a mass of 9.11 x 10^-31 kg, and charge qp = +e = +1.60 x 10^-19 C. It is moving towards an α particle (qα = +2e,

OlgaM077 [116]

Answer:

Part a)

$v = 2.25 \times 10^6 m/s$

Part b)

$r = 0.72 \times 10^{-10} m$

Explanation:

As we know that alpha particle remain at rest always so the energy of system of positron and alpha particle will remain constant

So we will have

$\frac{kq_1q_2}{r_1} + \frac{1}{2}mv_1^2 = \frac{kq_1q_2}{r_2} + \frac{1}{2}mv_2^2$

here we know that

$q_1 = 1.6 \times 10^{-19} C$

$q_2 = 2(1.6 \times 10^{-19}) C$

also we have

$r_1 = 2.00 \times 10^{-10} m$

$r_2 = 1.00 \times 10^{-10} m$

$v_1 = 3.00 \times 10^6 m/s$

$m = 9.11 \times 10^{-31} kg$

now from above equation we have

$2.304 \times 10^{-18} + 4.0995\times 10^{-18} = 4.608 \times 10^{-18} + \frac{1}{2}(9.11 \times 10^{-31})v^2$

$v = 2.25 \times 10^6 m/s$

Part b)

Now when it come to rest then again by energy conservation we can say

$\frac{kq_1q_2}{r_1} + \frac{1}{2}mv_1^2 = \frac{kq_1q_2}{r_2} + \frac{1}{2}mv_2^2$

now here final speed will be zero

$2.304 \times 10^{-18} + 4.0995\times 10^{-18} = \frac{(9/times 10^9)(1.6\times 10^{-19})(2\times 1.6 \times 10^{-19})}{r_2}$

$r = 0.72 \times 10^{-10} m$

7 0

3 years ago

A river flows due east at 1.50 m/s. A boat crosses the river from the south shore to the north shore by maintaining a constant v

monitta

Answer:

$u = 10.11 \ m/s$

$x = 44.996 \ m$

Explanation:

From the question we are told that

The velocity of the river due east is $v = 1.150i \ m /s$

The velocity of the boat due north is $v_1 = 10j \ m/ s$

The width of the river is $d = 300 \ m$

Generally the velocity of the boat relative to the shore

$u = \sqrt{v^2 + v_1^2}$

=> $u = \sqrt{1.50 ^2 + 10^2}$

=> $u = 10.11 \ m/s$

Generally direction of the boat relative to the shore is mathematically represented as

$tan \theta = \frac{v}{v_1}$

=> $\theta = tan^{-1}[ \frac{v}{v_1}]$

=> $\theta = tan^{-1}[ \frac{1.5}{10}]$

=> $\theta = 8.53^o$

Generally the distance covered by the boat in the direction of flow of the river before reaching the north shore is mathematically represented as

$x = d* tan(\theta )$

=> $x = 300 * tan(8.53)$

=> $x = 44.996 \ m$

3 0

3 years ago

If 600 N of force is used to move a car 4 meters, how much work is done?

slamgirl [31]

Answer:

<h3>The answer is 2400 J</h3>

Explanation:

The work done by an object can be found by using the formula

<h3>workdone = force × distance</h3>

From the question

force = 600 N

distance = 4 m

We have

work done = 600 × 4

We have the final answer as

Hope this helps you

4 0

3 years ago

1. Calculate the density of a 5.00 g marble which, when placed in a

gregori [183]

Answer:

1. 0.625 g/mL

2. 2×10⁵ J

3. 5040 J

4. 75000 J

Explanation:

1. Determination of the density.

We'll begin by calculating the volume of the marble. This can be obtained as follow:

Volume of water = 60 mL

Volume of water + Marble = 68 mL

Volume of marble =?

Volume of marble = (Volume of water + Marble) – (Volume of water)

Volume of marble = 68 – 60

Volume of marble = 8 mL

Finally, we shall determine the density of the marble. This can be obtained as follow:

Mass of marble = 5 g

Volume of marble = 8 mL

Density of marble =?

Density = mass / volume

Density of marble = 5 / 8

Density of marble = 0.625 g/mL

2. Determination of the work done.

Mass (m) = 1000 Kg

Height (h) = 20 m

Acceleration due to gravity (g) = 10 m/s²

Workdone (Wd) =?

The work done can be obtained as follow:

Wd = mgh

Wd = 1000 × 10 × 20

Wd= 2×10⁵ J

3. Determination of the potential energy.

Mass (m) = 12 Kg

Height (h) = 42 m

Acceleration due to gravity (g) = 10 m/s²

Potential energy (PE) =?

The potential energy can be obtained as follow:

PE = mgh

PE = 12 × 10 × 42

PE = 5040 J

4. Determination of the kinetic energy.

Mass (m) = 1500 Kg

Velocity (v) = 10 m/s

Kinetic energy (KE) =?

The kinetic energy can be obtained as follow:

KE = ½mv²

KE = ½ × 1500 × 10²

KE = 750 × 100

KE = 75000 J

6 0

3 years ago

Me izz in canada hehe Xd just in 2 mins wow what is immunization?

Kruka [31]

Answer:

Immunization, or immunisation, is the process by which an individual's immune system becomes fortified against an infectious agent.

Explanation:

HOPE IT HELPS 

HAVE A NICE DAY :) 

XXITZFLIRTYQUEENXX 

4 0

3 years ago