A train is accelerating at a rate of 2.0 km/hr squared. If it’s initial velocity is 20 km/hr, what is its velocity after 30 seco
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Answer:
the coefficients of static friction is 0.577
the coefficients of fkinetic friction is 0.54
Step-by-step explanation:
given information
θ = 30°
S = 2.5 m
t = 4 s
- Static friction
F - F(friction) = 0
W sin θ = μs W cos θ
μs = sin θ/ cosθ
= tan θ
= tan 30°
= 0.577
- kinetic friction
S = +
= 0
S =
a = =
= 0.3
F - F(friction) = m a
W sin θ - μ W cos θ = m a
mg sin θ - μk mg cos θ = m a
g sin θ - μk g cos θ = a
μk = g sin θ - a / g cos θ
= 9.8 sin 30° - 0.3 / 9.8 cos 30°
= 0.54