1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
pshichka [43]
3 years ago
15

If a bus traveled 20 miles north on a straight path, and then traveled 20 miles back to the starting point, what would the veloc

ity of the bus be?
0 mph

20 mph north

40 mph north

We do not have enough information.
Chemistry
2 answers:
Anestetic [448]3 years ago
7 0

Answer:i think its 20 mph north

Explanation:

vlada-n [284]3 years ago
3 0

Answer:

The correct answer is the option d: We do not have enough information.

Explanation:

Hello!

Let's solve this!

To calculate the speed we need the distance traveled and the time it takes to travel it.

The speed formula is

v = x2-x1 / t2-t1

x2: final position

x1: initial position

t2: final time

t1: initial time

In the case of this problem, we have the distance traveled, but we have no time in any case.

After the analysis, we conclude that the correct answer is the option d: We do not have enough information.

You might be interested in
Describe the charges of the particles in the atom and how charge is distributed within an atom.
trapecia [35]
There are MANY subatomic particles in an atom.
But the three most important ones are
The electron which has a negative charge.
The proton having a positive charge.
And the neutron which is neutral or which has no charge at all.
The protons and neutrons club together and form the inner, heavy part of the atom which is positively charges because of the protons known as the nucleus.
And electrons remain farther away in all reality and revolve around the inner positive nucleus.
Trying its best to make the whole atom neutral!
8 0
3 years ago
An acid-base indicator is used in what type of reaction?
Temka [501]
Acid - base indicators (also known as pH indicators) are substances which change color with pH. They are usually weak acids or bases. you use them if you want to know if a solution is an acid or it it's a base
4 0
3 years ago
You calculate that your semester average in history is 97.5. When you get your report card, your average is 96. What was the per
andrew11 [14]
Ok percent error is abs(calculated-actual)/actual(100%)

So 1.5/96 *100%
5 0
3 years ago
Read 2 more answers
Convert 22 ml in to liters
prisoha [69]

Answer:

0.022

Explanation:

milliter (ml) = 1 cubic centimeter (cc)= 0.001 liters (l) = 0.000001 cubic meters (m3).

1 ml = 0.061024 cubic inches (in3) ; 1 in3 = 16.4 ml.

1 ml = 0.000035 cubic feet (ft3); 1 ft3 = 28,317 ml.

1 ml = 2.64 x 10-4 U.S. gallons (gal); 1 gal = 4.55 x 103 ml.

8 0
3 years ago
Air at 25°C with a dew point of 10 °C enters a humidifier. The air leaving the unit has an absolute humidity of 0.07 kg of water
madreJ [45]

Explanation:

The given data is as follows.

         Temperature of dry bulb of air = 25^{o}C

          Dew point = 10^{o}C = (10 + 273) K = 283 K

At the dew point temperature, the first drop of water condenses out of air and then,

        Partial pressure of water vapor (P_{a}) = vapor pressure of water at a given temperature (P^{s}_{a})

Using Antoine's equation we get the following.

            ln (P^{s}_{a}) = 16.26205 - \frac{3799.887}{T(K) - 46.854}

            ln (P^{s}_{a}) = 16.26205 - \frac{3799.887}{283 - 46.854}

                               = 0.17079

                   P^{s}_{a} = 1.18624 kPa

As total pressure (P_{t}) = atmospheric pressure = 760 mm Hg

                                   = 101..325 kPa

The absolute humidity of inlet air = \frac{P^{s}_{a}}{P_{t} - P^{s}_{a}} \times \frac{18 kg H_{2}O}{29 \text{kg dry air}}

                  \frac{1.18624}{101.325 - 1.18624} \times \frac{18 kg H_{2}O}{29 \text{kg dry air}}

                 = 0.00735 kg H_{2}O/ kg dry air

Hence, air leaving the humidifier has a has an absolute humidity (%) of 0.07 kg H_{2}O/ kg dry air.

Therefore, amount of water evaporated for every 1 kg dry air entering the humidifier is as follows.

                 0.07 kg - 0.00735 kg

              = 0.06265 kg H_{2}O for every 1 kg dry air

Hence, calculate the amount of water evaporated for every 100 kg of dry air as follows.

                0.06265 kg \times 100

                  = 6.265 kg

Thus, we can conclude that kg of water the must be evaporated into the air for every 100 kg of dry air entering the unit is 6.265 kg.

3 0
3 years ago
Other questions:
  • 7. A 1.50 x 103 kg car accelerates uniformly from rest to 10.0 m/s in 3.00 s.
    6·1 answer
  • On a shade-grown coffee plantation, smaller coffee plants grow in the shade of forest trees. The practice produces fewer coffee
    14·2 answers
  • A cup of sugar has a volume of 237 ml. What is the mass of the сup of sugar if the density is 1.59 g/mL?
    7·1 answer
  • Place the following substances in Order of decreasing boiling point H20 N2 CO
    9·2 answers
  • How many grams of AgCl are produced from 10.0 g AgNO3?
    11·1 answer
  • What are communities doing to prepare for this hazard? Hurricane
    8·2 answers
  • Why do strong bonds exist between water molecules?
    5·1 answer
  • How many grams are in the quantity: 2.5 mol of NaCl
    5·2 answers
  • If you have 250mL of an 11M solution and add enough water to dilute it to 7 M, then what is the final volume of the solution?
    8·1 answer
  • Which statement describes one feature of Rutherford model of the atom
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!