Answer:
Equation of Reaction = AgNO3 (aq) + NaCl (aq) → AgCl (s) + NaNO3 (aq)
<u>Steps:</u>
1. Find the moles of AgNO3 with formula n= Mass/Mr (molecular mass)
so you will get moles= 10.0/ 169.87 = 0.05886854654
2. Using stoichiometry you know the equation has 1 mole so the moles of AgCl are gonna be the same; therefore, you will use again the same formula.
3. moles= mass/molecular mass
0.05886854654 = x/ 143.32
You rearrange the formula to find the mass
so mass = moles x molecular mass
mass = 0.05886854654 x 143.32
mass= 8.44 grams
Explanation:
