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Thepotemich [5.8K]
2 years ago
11

How many grams of AgCl are produced from 10.0 g AgNO3?

Chemistry
1 answer:
irina1246 [14]2 years ago
5 0

Answer:

Equation of Reaction = AgNO3 (aq) + NaCl (aq) → AgCl (s) + NaNO3 (aq)

<u>Steps:</u>

1. Find the moles of AgNO3 with formula n= Mass/Mr (molecular mass)

so you will get moles= 10.0/ 169.87 = 0.05886854654

2. Using stoichiometry you know the equation has 1 mole so the moles of AgCl are gonna be the same; therefore, you will use again the same formula.

3.  moles= mass/molecular mass

0.05886854654 = x/ 143.32

You rearrange the formula to find the mass

so mass = moles x molecular mass

mass = 0.05886854654 x 143.32

mass= 8.44 grams

Explanation:

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Atoms that have the same number of outer electrons
BARSIC [14]
I can see two answers, I’d go with D, but all neutral atoms, of the same element would have the same number of outer electrons. However, if you consider that some of the atoms might be ions, that would eliminate B.
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3 years ago
1. The solubility of AgNO3 at 20°C is 222.0g AgNO3/100g H2O. What mass of AgNO3 can be dissolved in 250 g of water at 20°C? Reca
neonofarm [45]

Answer :

(1) The mass of silver nitrate is, 555 g

(2) The solubility of the gas will be, 0.433 g/L

<u>Solution for Part 1 :</u>

From the given data we conclude that

In 100 gram of water, the amount of silver nitrate = 222 g

In 250 gram of water, the amount of silver nitrate = \frac{222}{100}\times 250=555g

Therefore, the mass of silver nitrate is, 555 g

<u>Solution for Part 2 :</u>

Formula used : S_1P_1=S_2P_2     (at constant temperature)

where,

S_1 = initial solubility of methane gas = 0.026 g/L

S_2 = final solubility of methane gas

P_1 = initial pressure of methane gas = 1 atm

P_2 = final pressure of methane gas = 0.06 atm

Now put all the given values in the above formula, we get the solubility of methane gas.

(0.026g/L)\times (1atm)=S_2\times (0.06atm)

S_2=0.433g/L

Therefore, the solubility of the gas will be, 0.433 g/L

5 0
3 years ago
What is paper chromatography? Calculate the Rr value of a colored dye that traveled 52 mm on a chromatography strip while the so
Karo-lina-s [1.5K]

Answer:

Paper chromatography is a basic technique of chromatography. It consist in the separation of the mixe components using a solvent.

Explanation:

Paper chromatography is a basic technique of chromatography. It consists in the separation of the mixed components using a solvent.

Paper chromatography consists of put some dot of the mix using a glass capillary into a specialized paper, generally made of cellulose, this is called a stationary phase.

Then you put this paper into a camera of glass named, chromatography camera, where previously contain a solvent. The solvent also know as a mobile phase, the type can be defined before the test and involves a study of the kind of the mix, and the compound you want to separate.

The chromatography camera has to be closed all the time during the test, and you can't move at all because the movement of the solvent can alternate the result.

Very often, the solution of the solvent is a mix of different liquid substances with different polarities.

When the stationary phase put into the camera, the solvent starts to move up over the paper, until the separation of the compounds is observable.

the Rf is a value who relates the move of the mobile phase with the move of the distance traveled by the substance tested.

To undersant the paper chromatography, you can watch the images attached.

The first is an image of the chromatography camera.

The second one is an image of a cellulose paper after the chromatography is done. You can watch the dots who indicates the traveling of the compound across the paper.

The third one can show you the evolutions of paper chromatography, from the beginning to the end.

To calculate the Rf value you have to use the equation:

Rf = distance traveled by the substance/distance traveled by the solvent/

<u>Rf = 52mm/81mm =0.64</u>

<u></u>

3 0
3 years ago
70 oz of protein how many grams of protein are
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There is a bout 7 grams of protein in 1 ounce of meat, so 7*70=
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Read 2 more answers
What volume of a 1.5 M KOH solution is needed to provide 3.0 moles of KOH?
Brums [2.3K]

Answer:

  • Volume = <u>2.0 liter</u> of 1.5 M solution of KOH

Explanation:

<u>1) Data:</u>

a) Solution: KOH

b) M = 1.5 M

c) n = 3.0 mol

d) V = ?

<u>2) Formula:</u>

Molarity is a unit of concentration, defined as number of moles of solute per liter of solution:

  • M = n / V in liter

<u>3) Calculations:</u>

  • Solve for n: M = n / V ⇒ V = n / M

  • Substitute values: V = 3.0 mol / 1.5 M = 2.0 liter

You must use 2 significant figures in your answer: <u>2.0 liter.</u>

8 0
2 years ago
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