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2 years ago

Convert 22 ml in to liters

Chemistry

1 answer:

prisoha [69]2 years ago

8 0

Answer:

0.022

Explanation:

milliter (ml) = 1 cubic centimeter (cc)= 0.001 liters (l) = 0.000001 cubic meters (m3).

1 ml = 0.061024 cubic inches (in3) ; 1 in3 = 16.4 ml.

1 ml = 0.000035 cubic feet (ft3); 1 ft3 = 28,317 ml.

1 ml = 2.64 x 10-4 U.S. gallons (gal); 1 gal = 4.55 x 103 ml.

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A gas of 3.4 moles occupies a volume of 0.046 L at 298 K. What is the pressure in kPa?

Phantasy [73]

Answer : The correct option is, $2.1\times 10^5kPa$

Explanation :

To calculate the pressure of gas we are using ideal gas equation as:

$PV=nRT$

where,

P = pressure of gas = ?

V = volume of gas = 0.046 L

n = number of moles of gas = 3.4

R = gas constant = 8.314 L.kPa/mol.K

T = temperature of gas = 298 K

Now put all the given values in the above formula, we get:

$P\times (0.046L)=(3.4mol)\times (8.314L.kPa/mol.K)\times (298K)$

$P=1.83\times 10^5kPa\approx 2.1\times 10^5kPa$

Therefore, the pressure of gas is, $2.1\times 10^5kPa$

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2 years ago

Find the volume of an object that has a density 0f 3.14g/mL and a mass of 87.3g

pav-90 [236]

Answer:

<h3>The answer is 27.80 mL</h3>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

$volume = \frac{mass}{density} \\$

From the question

mass = 87.3 g

density = 3.14 g/mL

We have

$volume = \frac{87.3}{3.14} \\ = 27.8025477...$

We have the final answer as

Hope this helps you

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2 years ago

Carbon cycle is returned to the atmosphere primarily by the respiration of consumer.

natima [27]

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A 5% Dextrose solution is diluted with sterile water. The volume of the sterile water added is 40% of the volume of the Dextrose

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Answer:

4.90% is approximately the new Dextrose concentration.

Explanation:

Volume by Volume percent is given by ;

$(v/v)\%=\frac{\text{Volume of solute}}{\text{Volume of solution}}\times 100$

Volume percentage of dextrose solution = 5%

In 100 mL of solution 5 ml of dextrose is present.

Now, volume sterile water added was equal to the 40% of volume of dextrose volume.

So, volume of the sterile water added = $\frac{40}{100}\times 5 ml = 2 mL$

Total volume of the solution after addition of water = 100 mL + 1 mL = 102 mL

New concentration of dextrose will be;

$(v/v)\%=\frac{\text{Volume of solute}}{\text{Volume of solution}}\times 100$

$\frac{5 mL}{102 mL}\times 100=4.90\%$

4.90% is approximately the new Dextrose concentration.

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Answer:

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