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scZoUnD [109]
3 years ago
6

Convert 22 ml in to liters

Chemistry
1 answer:
prisoha [69]3 years ago
8 0

Answer:

0.022

Explanation:

milliter (ml) = 1 cubic centimeter (cc)= 0.001 liters (l) = 0.000001 cubic meters (m3).

1 ml = 0.061024 cubic inches (in3) ; 1 in3 = 16.4 ml.

1 ml = 0.000035 cubic feet (ft3); 1 ft3 = 28,317 ml.

1 ml = 2.64 x 10-4 U.S. gallons (gal); 1 gal = 4.55 x 103 ml.

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A chemist mixes 1.00 g CuCl2 with an excess of (NH4)2HPO4 in dilute aqueous solution . He measures the evolution of 670 J of hea
kaheart [24]

Answer:

\Delta H will be 90054 J

Explanation:

Number of moles = (mass)/(molar mass)

Molar mass of CuCl_{2} = 134.45 g/mol

So, 1.00 g of CuCl_{2} = \frac{1.00}{134.45}mol of CuCl_{2} = 0.00744 mol of CuCl_{2}

0.00744 mol of CuCl_{2} produces 670 J of heat

So, 1 mol of CuCl_{2} produces \frac{670}{0.00744}J of heat or 90054 J of heat

4 0
4 years ago
Arsenic reacts with chlorine to form a chloride if 1.587 g of arsenic reacts with 3.755 g of chlorine what is the simplest formu
Marina CMI [18]
<span>Determining the number chloride molecules that will result from this reaction requires we first determine the number of moles of arsenic and the number of moles of chlorine on hand.

1.587 grams of arsenic divided by its atomic weight of 74.92 grams per mole results in 0.0212 moles.

We do the same for chlorine. 2.755 grams of chlorine divided by 35.45 grams per mole gives us 0.106 moles.
0.106 moles divided by .0212 moles equals 5; therefore, the simplest formula of the chloride produced will be AsCl</span>₅<span>.</span>
8 0
3 years ago
2NO + 3MnO2 + 4H â 2NO3- + 3Mn2 + 2H2O For the above redox reaction, assign oxidation numbers and use them to identify the eleme
mixer [17]

Answer:

Manganese decreases from 4+ to 2+ (reduced and oxidizing agent) and nitrogen increases from 2+ to 5+ (oxidized and reducing agent).

Explanation:

Hello there!

In this case, according to the given redox reaction, we rewrite it as a convenient first step:

2NO + 3MnO_2 + 4H^+ \rightarrow 2NO_3^- + 3Mn^{2+} + 2H_2O

Next, we assign the oxidation numbers as follows:

2N^{2+}O^{2-} + 3Mn^{4+}O^{-2}_2 + 4H^+ \rightarrow 2(N^{5+}O^{2-}_3)^- + 3Mn^{2+} + 2H^+_2O^{2-}

Thus, we can see that both manganese and nitrogen undergo a change in their oxidation number, the former decreases from 4+ to 2+ (reduced and oxidizing agent) and the latter increases from 2+ to 5+ (oxidized and reducing agent).

Regards!

4 0
3 years ago
How much energy is released when 65.8 g of water freezes
Delvig [45]

The amount of energy released is calculated by the product of heat of fusion and mass. The formula of amount energy released is given by: q= L\times m                (1)

Here,  

q is amount of energy released L is heat of fusion (334 J/g) m is mass of water Put all the given values in equation (1)

q= 334 J/g \times 65.8 g

q= 21977.2 Joules ≅ 21977 Joules

q= 21977 Joules

Thus, amount of energy released is 21977 Joules


6 0
3 years ago
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The churning air in the troposphere helps determine the of a place
Arturiano [62]
The answer is the climate of a place. The troposphere is the lowermost level of Earth's air, and is likewise where closely all weather and climate situations happen. It covers about 75% of the air's mass and 99% of the total form of water vapor and aerosols.
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