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algol [13]
2 years ago
10

The lengths of the sides of a triangle are in the extended ratio 4 : 9 : 10. The perimeter of the triangle is 92 cm. What are th

e lengths of the sides?
Mathematics
1 answer:
Nookie1986 [14]2 years ago
7 0
16, 36, 40

Set the problem up as 4x+9x+10x= 92

26x= 92

X= 4

Plug back in to get the lengths of the sides (shown above)
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A taco stand sells tacos for $3.25 each. The stands expenses for the day are $210. Define your variables and write an inequality
Julli [10]
Given:

Let P= profit
let n= no. of tacos sold per day

Sol'n:

P= 3.25n-210
the profit needs to be positive, thus

3.25n>210

n>210/3.25

n> 64.615

they can only sell whole tacos, therefore they must sell at least 65 tacos to make a profit and that profit is:

P=3.25n-210

P=3.25*65 - 210

P= 211.25 -210

P= 1.25

$1.25 profit
3 0
3 years ago
A random sample of 10 parking meters in a beach community showed the following incomes for a day. Assume the incomes are normall
Vlad1618 [11]

Answer: (2.54,6.86)

Step-by-step explanation:

Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.

We assume the incomes are normally distributed.

Mean income : \mu=\dfrac{\sum^{10}_{i=1}x_i}{n}=\dfrac{47}{10}=4.7

Standard deviation : \sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}

=\sqrt{\dfrac{(1.1)^2+(0.2)^2+(1.9)^2+(1.6)^2+(2.1)^2+(0.5)^2+(2.05)^2+(0.45)^2+(3.3)^2+(1.7)^2}{10}}

=\dfrac{30.265}{10}=3.0265

The confidence interval for the population mean (for sample size <30) is given by :-

\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}

Given significance level : \alpha=1-0.95=0.05

Critical value : t_{n-1,\alpha/2}=t_{9,0.025}=2.262

We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)

Hence, 95% confidence interval for the true mean= (2.54,6.86)

7 0
3 years ago
Can someone please help me!?!?!?
sineoko [7]

3. Alt. Interior Angles

4. definition of midpoint

5 0
2 years ago
At a certain time of day, a vertical pole 8ft high casts a 5ft shadow. How long is the shadow of a 4ft child?
snow_tiger [21]
We can look at 2 similar triangles.
1st triangle has legs: a vertical pole and its shadow, and
2nd triangle has legs legs : a child and his(her) shadow.

We can write a proportion:
height of a pole/height of a child= shadow of a pole/shadow of a child

8/4 = 5/shadow of a child
shadow of a child=(5*4)/8=5/2 ft
Answer: 5/2 ft

8 0
3 years ago
Jamie is wrapping a can of paint as a gag gift for a friend. If the can is 11 inches high and has a diameter of 7 inches, how ma
Rudiy27
A can of paint is a cylinder, so we must use the surface area for a cylinder.
2(\pirr^{2}) is the top and bottom.

The surface of the can is a rectangle with a length equal to the circumference of the can.

4 0
3 years ago
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