What is the vertex of the quadratic function f(x)=(x-6)(x+2)
1 answer:
Answer: ( 2, -6 )
Step-by-step explanation:
rewrite y= (x-6)(x+2) in the form y=ax^2+bx+c
Y=(x-6)(x+2)
(x-6)(x+2): x^2-4x-12
y=x^2-4x-12
the parabola params are :
a=1, b= -4, c=-12
x^v=-(-4)/ 2*1
x^v=2
y^v=-16
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