Answer:
80.7lbft/hr
Explanation:
Flow rate of water in the system = 3.6x10^-6
The height h = 100
1s = 1/3600h
This implies that
Q = 3.6x10^-6/[1/3600]
Q = 0.0000036/0.000278
Q = 0.01295
Then the power is given as
P = rQh
The specific weight of water = 62.3 lb/ft³
P = 62.3 x 0.01295 x 100
P = 80.675lbft/h
When approximated
P = 80.7 lbft/h
This is the average power that could be generated in a year.
This answers the question and also corresponds with the answer in the question.
To solve this problem it is necessary to apply the concepts related to density in relation to mass and volume for each of the states presented.
Density can be defined as

Where
m = Mass
V = Volume
For state one we know that




For state two we have to




Therefore the total change of mass would be



Therefore the mass of air that has entered to the tank is 6.02Kg
Answer:
$5.184
Explanation:
The cost can be calculated using the formula: 
Before using this, we require the following conversions:
<em>320 W → kW:</em>
<em>30 Days → Hours:</em>

Using the above stated formula:

If your accelerator gets stuck down, do the following: Shift to neutral. Apply the brakes. Keep your eyes on the road and look for a way out.If your accelerator gets stuck down, do the following:
Shift to neutral.
Apply the brakes.
Keep your eyes on the road and look for a way out.
Warn other drivers by blinking and flashing your hazard lights.
Try to drive the car safely off the road.
Turn off the ignition when you no longer need to change direction.