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3 years ago

10

Are the wooden pillars shown in the image below, a dead load?

1 answer:

Brrunno [24]3 years ago

6 0

Answer:

no

Explanation:

it's not a dead load because when load is put on the pillars it's not fully straining it's been slowly getting to be heavier in that period of time before it falls

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Air expands through an ideal turbine from 1 MPa, 900 K to 0.1 MPa, 500K. The inlet velocity is small compared to the exit veloci

3241004551 [841]

Answer:

Mass flow rate= 7.53 kg/sec

Exit Area= 0.108m^2

Explanation:

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3 years ago

Which of the following can cause a flopping sound at the front of the engine

Irina-Kira [14]

B) timing chain too loose

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3 years ago

Technician A says that the starter solenoid switches the high current on and off. Technician B says that the solenoid on the sta

jek_recluse [69]

Technician A is incorrect so that means Technician B is correct.

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3 years ago

Match the scenario to the term it represents.

Ann [662]

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3 years ago

In order to fill a tank of 1000 liter volume to a pressure of 10 atm at 298K, an 11.5Kg of the gas is required. How many moles o

lesya [120]

Answer:

The molecular weight will be "28.12 g/mol".

Explanation:

The given values are:

Pressure,

P = 10 atm

= $10\times 101325 \ Pa$

= $1013250 \ Pa$

Temperature,

T = 298 K

Mass,

m = 11.5 Kg

Volume,

V = 1000 r

= $1 \ m^3$

R = 8.3145 J/mol K

Now,

By using the ideal gas law, we get

⇒ $PV=nRT$

o,

⇒ $n=\frac{PV}{RT}$

By substituting the values, we get

$=\frac{1013250\times 1}{8.3145\times 298}$

$=408.94 \ moles$

As we know,

⇒ $Moles(n)=\frac{Mass(m)}{Molecular \ weight(MW)}$

or,

⇒ $MW=\frac{m}{n}$

$=\frac{11.5}{408.94}$

$=0.02812 \ Kg/mol$

$=28.12 \ g/mol$

3 0

3 years ago