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2 years ago

Are the wooden pillars shown in the image below, a dead load?

Engineering

1 answer:

Brrunno [24]2 years ago

6 0

Answer:

Explanation:

it's not a dead load because when load is put on the pillars it's not fully straining it's been slowly getting to be heavier in that period of time before it falls

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Diffrent ways to make a header above a window

Oliga [24]

Answer: double click at the top of the page. Or you can also go to home file and click add heading.

Explanation:

5 0

2 years ago

If you measure 0.7 V across a diode, the diode is probably made of

tatuchka [14]

Answer:

Made of Silicon.

Explanation:

A diode is a semiconductor device use in mostly electronic appliances. It is two terminals device consisting of a P-N junction formed either in Germanium or silicon crystal.

Diode can be forward biased or reverse biased.

When a diode is forward biased and the applied voltage is increased from zero, hardly any current flows through the device in the beginning.

It is so because the external voltage is being opposed by the internal barrier voltage whose value is 0.7v for silicon and 0.3v for germanium.

If you measure 0.7 V across a diode, the diode is probably therefore made of Silicon.

6 0

2 years ago

Suppose values is a sorted array of integers. Give pseudocode that describes how a new value can be inserted so that the resulti

Novosadov [1.4K]

Answer:

insert (array[] , value , currentsize , maxsize )

{

if maxsize <=currentsize

{

return -1

}

index = currentsize-1

while (i>=0 && array[index] > value)

{

array[index+1]=array[index]

i=i-1

}

array[i+1]=value

return 0

}

Explanation:

1: Check if array is already full, if it's full then no component may be inserted.

2: if array isn't full:

Check parts of the array ranging from last position of range towards initial range and determine position of that initial range that is smaller than the worth to be inserted.
Right shift every component of the array once ranging from last position up to the position larger than the position at that smaller range was known.

assign new worth to the position that is next to the known position of initial smaller component.

7 0

2 years ago

Draw a radial power circuit arrangement containing 3 single fused sockets and 2 double unfused sockets showing the live, earth a

sweet [91]

Answer:

Attached below is the Radial power circuit arrangement

Explanation:

Radial power circuit arrangement is done in a way that a single cable starts from the fuse box and connects to all the outlet socket contained in the circuit also the cable contains wires ( live , neutral and earth )

The advantage of a radial power circuit arrangement is that it enables easy identification of electrical faults on the circuit.

4 0

2 years ago

A fluid with a relative density of 0.9 flows in a pipe which is 12 m long and lies at an angle of 60° to the horizontal At the t

Minchanka [31]

Answer:

$Q=7.3\times 10^{-3} m^3/s$

Explanation:

Given that

At top $d_2=30 mm,P_2=860 KPa ,P_1=1000 KPa,d_1=85 mm$

$\rho =900\dfrac{Kg}{m^3}$

We know that

$\dfrac{P_1}{\rho g}+\dfrac{V_1^2}{2g}+Z_1=\dfrac{P_2}{\rho g}+\dfrac{V_2^2}{2g}+Z_2$

$A_1V_1=A_2V_2$

$\frac{V_1}{V_2}=\left(\dfrac{d_2}{d_1}\right)^2$

$\frac{V_1}{V_2}=\left(\dfrac{30}{85}\right)^2$

$V_2=8.02V_1$

$Z_2=12 sin60^{\circ}$

$\dfrac{1000\times 1000}{900\times 9.81}+\dfrac{V_1^2}{2\times 9.81}+0=\dfrac{860\times 1000}{900\times 9.81 }+\dfrac{V_2^2}{2\times 9.81}+12 sin60^{\circ}$

So $V_1=1.30$ m/s

We know that flow rate Q=AV

$Q=A_1V_1$

By putting the values

$A_1=\dfrac{\pi}{4}d^2$

$Q=7.3\times 10^{-3} m^3/s$

To find the flow rate we do not need the direction of flow,because we are just doing balancing of energy at inlet and at the exits of pipe.

4 0

2 years ago