Answer: the final temperature of the steam 581.5 °C
Explanation:
Given that;
P₁ = 11 MPa
T₁ = 600°C
exit at; P₂= 5.5 MPa
Now from superheated steam table( p=11 MPa, T=600°C)
h₁ = 3615 kJ/kg
h₁ = h₂ ( by throttling process and adiabatic isentholpic )
from saturated steam table at; ( h= 3615 kJ/kg, P= 5.5 MPa )
Temperature = 581.5 °C
Therefore the final temperature of the steam 581.5 °C
Answer:
i believe the answer is a but i could be wrong
Explanation:
i hope it helps
Answer:
Explanation:
From the information given:
The total load is distributed across both the rod and tube:
Since this is a composite column; the elongation of both aluminum rod & steel tube is equal.
Replace 
into equation (1)
Finally, to determine the normal stress in aluminum rod:
Thus, the normal stress = 23.523 MPa in compression.
Answer:
The power developed in HP is 2702.7hp
Explanation:
Given details.
P1 = 150 lbf/in^2,
T1 = 1400°R
P2 = 14.8 lbf/in^2,
T2 = 700°R
Mass flow rate m1 = m2 = m = 11 lb/s Q = -65000 Btu/h
Using air table to obtain the values for h1 and h2 at T1 and T2
h1 at T1 = 1400°R = 342.9 Btu/h
h2 at T2 = 700°R = 167.6 Btu/h
Using;
Q - W + m(h1) - m(h2) = 0
W = Q - m (h2 -h1)
W = (-65000 Btu/h ) - 11 lb/s (167.6 - 342.9) Btu/h
W = (-65000 Btu/h ) - (-1928.3) Btu/s
W = (-65000 Btu/h ) * {1hr/(60*60)s} - (-1928.3) Btu/s
W = -18.06Btu/s + 1928.3 Btu/s
W = 1910.24Btu/s
Note; Btu/s = 1.4148532hp
W = 2702.7hp
Answer:
Fluids
Explanation:
Fluids has special properties that allow forces and pressure to be distributed evenly within them.
- Fluids are gases and liquids whose intermolecular forces of attraction are generally weak or non-existence.
- Therefore, when pressure is applied to them, it permeates evenly on all parts.
- Their ability to tend to randomness makes liquids and gases very viable for distributing pressure.
