Answer:
2ib
Explanation:
if you divide 10 divided by 2 it gives you 5 and then subtract it by 2.2 = 2.8
there goes your answer.
Answer:
Yes, the flow is turbulent.
Explanation:
Reynolds number gives the nature of flow. If he Reynolds number is less than 2000 then the flow is laminar else turbulent.
Given:
Diameter of pipe is 10mm.
Velocity of the pipe is 1m/s.
Temperature of water is 200°C.
The kinematic viscosity at temperature 200°C is
m2/s.
Calculation:
Step1
Expression for Reynolds number is given as follows:

Here, v is velocity,
is kinematic viscosity, d is diameter and Re is Reynolds number.
Substitute the values in the above equation as follows:


Re=64226.07579
Thus, the Reynolds number is 64226.07579. This is greater than 2000.
Hence, the given flow is turbulent flow.
Answer:
a) 2∪p/lb (l+b)dH
b) po exp( 4∪x/l)
Explanation:
please check the attachment for proper explanation and proper sign notations thanks.
Answer:
0.264 ; 0.079
Explanation:
Given that:
Sample size, n = 100
Probability of being active, p = 1% = 1/100 = 0.01
Using the binomial probability relation :
P(x =x) = nCx * p^x * (1 - p)^(n - x)
Probability that more than 1 user will be active
P(x > 1) = 1 - [p(x=0) + p(x = 1)]
P(x = 0) = 100C0 * 0.01^0 * 0.99^100 = 0.366
P(x = 1) = 100C1 * 0.01^1 * 0.99^99 = 0.370
P(x > 1) = 1 - [0.366 + 0.370]
P(x > 1) = 0.264
2.)
Probability that more than 2 user will be active
P(x > 2) = 1 - [p(x=0) + p(x = 1) + p(x = 2)]
P(x = 0) = 100C0 * 0.01^0 * 0.99^100 = 0.366
P(x = 1) = 100C1 * 0.01^1 * 0.99^99 = 0.370
P(x = 2) = 100C2 * 0.01^2 * 0.99^98 = 0.185
P(x > 1) = 1 - [0.366 + 0.370 + 0.185]
P(x > 1) = 0.079