Answer:
Given
inlet Pga =40kpa = 40000pa
Patm=1.01bar = 1.01 x 100000pa =101000pa
exit Pab= 6.5 (inlet Pab)
But generally, Pab = Patm + Pga
1. the absolute pressure of the gas at the inlet, inlet Pab?
inlet Pab = Patm + inlet Pga
= 101000pa + 40000pa = 141kpa
the absolute pressure of the gas at the inlet, inlet Pab = 141kpa
2. the gage pressure of the gas at the exit? exit Pga?
exit Pab = Patm + exit Pga
exit Pga = exit Pab - Patm
= (6.5 x 141kpa) - 101kpa
= 815.5kpa
the gage pressure of the gas at the exit exit Pga=815.5kpa
Drafting has been around a long time. We can safely assume that since we’ve had a tool in our hands, we’ve been describing plans and technical representations and doodling ideas. Let’s take a closer aspect at drafting and its advance from an under-the-radar part of the method to a very developed skill set.
<u>Explanation</u>
• 1970s – The beginning computer-aided design systems were included in the industry. Following the design engineers tried the learning curve of using CAD, their performance and productivity went through the roof. Over time, CAD software became affordable and more user-friendly, and its fame grew.
• 1990s – CAD software was expanded further to include 3-D characteristics, and quickly the technical designs of the past enhanced increasingly simulated and accessible to engineer.
• Present – The development of drafting has brought us to the present day, were using 3-D representations is the standard and the aim to generate full virtual prototypes.
Answer:a
a) Vo/Vi = - 3.4
b) Vo/Vi = - 14.8
c) Vo/Vi = - 1000
Explanation:
a)
R1 = 17kΩ
for ideal op-amp
Va≈Vb=0 so Va=0
(Va - Vi)/5kΩ + (Va -Vo)/17kΩ = 0
sin we know Va≈Vb=0
so
-Vi/5kΩ + -Vo/17kΩ = 0
Vo/Vi = - 17k/5k
Vo/Vi = -3.4
║Vo/Vi ║ = 3.4 ( negative sign phase inversion)
b)
R2 = 74kΩ
for ideal op-amp
Va≈Vb=0 so Va=0
so
(Va-Vi)/5kΩ + (Va-Vo)74kΩ = 0
-Vi/5kΩ + -Vo/74kΩ = 0
Vo/Vi = - 74kΩ/5kΩ
Vo/Vi = - 14.8
║Vo/Vi ║ = 14.8 ( negative sign phase inversion)
c)
Also for ideal op-amp
Va≈Vb=0 so Va=0
Now for position 3 we apply nodal analysis we got at position 1
(Va - Vi)/5kΩ + (Va - Vo)/5000kΩ = 0 ( 5MΩ = 5000kΩ )
so
-Vi/5kΩ + -Vo/5000kΩ = 0
Vo/Vi = - 5000kΩ/5kΩ
Vo/Vi = - 1000
║Vo/Vi ║ = 1000 ( negative sign phase inversion)
Answer:
The correct answer is 'velocity'of liquid flowing out of an orifice is proportional to the square root of the 'height' of liquid above the center of the orifice.
Explanation:
Torricelli's theorem states that
where
is the velocity with which the fluid leaves orifice
is the head under which the flow occurs.
Thus we can compare the given options to arrive at the correct answer
Velocity is proportional to square root of head under which the flow occurs.